PROFESSOR: And I didn't write up there but it is one, 1 and we can see that it's 1, 2 because it's 1/2 of 2, 4 minus 2, so 1/2 of 2, the bonding order is going to be equal to one.

教授：我没有写出来，但是是1，我们可以看到为什么是，因为它等于1/2的2，4减去，所以1/2的2，键序等于1。

麻省理工公开课 - 化学原理课程节选

So for the bond order we want to take 1/2 of the total number of bonding electrons, so that's going to be 4 minus anti-bonding is 4, so we end up getting a bond order that's equal to 0.

键序等于1/2乘以,总的成键电子数，也就是4，减去反键电子数，也就是4。,所以最后得到键序为0。

麻省理工公开课 - 化学原理课程节选

So we would predict a bond order of 1.

所以我们预测键序是。

麻省理工公开课 - 化学原理课程节选

So our bond order for h e 2 is going to be equal to 0.

所以He2的键序等于0。

麻省理工公开课 - 化学原理课程节选

OK PROFESSOR: two? OK, 2 so we have 2, 4, 6 minus 2, 2 so we have 1/2 of 6 minus 2, so that's 1/2 half 4, so we have a bonding order of two for carbon 2.

教授：两个？,我们有2，4，6减去，所以我们有1/2的6减去，所以是4的一半，所以C2的键序为2。

麻省理工公开课 - 化学原理课程节选