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So, inside of code, or inside of a script, there's no print, unless we make it explicit.
因此，在代码里面，或者在脚本里面，不会有显示结果的功能，除非我们让它这么做。
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And they're awfully simple because, all I can do now, is decide whether to execute some piece of code or another.
它们之所以太简单的原因是：,现在我能做的，就是,决定执行一块代码或者执行另外一块。
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The idea of a "code walkthrough" refers to the process of walking through your code verbally or visually with or without other people.
代码走查“的概念是单独或者和别人一起,通过查看或讨论学习你们的代码,的一个过程。
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In a compiled language, you have an intermediate step, in which you take the source code, it runs through what's called a checker or a compiler or both, and it creates what's called object code.
而在编译语言里，你就会经过一个中间的步骤，在这种语言里输入源码后，先经过过滤器,或者编译器检查后，它会创建一个叫做目标代码的东西。
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By the time you get to the end of the term, you're going to be dealing with some fairly complex things, so one of the things you're going to see is, we're going to make heavy use of libraries, or code written by others.
当你临近期末的时候，你们将要解决一些,相当复杂的难题，因此你们将会看到的其中一点是，我们要充分利用图书馆，或者别人编写的代码。
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It's words to you, or to the reader of the code, that are telling you what's going on inside of this code. OK?
注释是一些对你，或者对代码阅读者说的一些话，告诉你这段代码,是干什么的，对不对？
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All that's going to change, is the value the variable or the value of some data structures.
或者一些数据结构的值,提醒大家在这块代码里面。
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If you want to make sure both conditions are true and they both have to be true for any code to be executed, use ampersand ampersand.
如果你想保证两个条件都成立,或者它们两个都必须为真值，才能执行一些代码，那就使用“&&“
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hey'd rather single step it through using Idol or something, than just read it and try and figure things out. The most important thing to remember when you're doing all of this is to be systematic.
比起阅读代码发现错误来他们,宁愿用内置的操作层,或者其他工具一步完成,你要记住的最重要的事情,就是要系统化的去做调试。
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When we start building up code, we're going to use commands. Or statements.
当我们写代码的时候，我们会用到命令或者声明。
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I just reran make or GCC does it for me, and now I've got all these errors. Well, let's see.
我刚重新运行了make，或者GCC为我编译了代码，现在我得到了这些错误，好的，让我们看看。
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So input is an int called F, print out to the screen or your piece of paper the value of C. Odds are you only need two, maybe three lines of code for this, but the goal ultimately will be try it on your own.
所以输入是一个int类型的F，在你的屏幕上,或你们的纸上打印出C的数值,可能你们需要两行或者三行的代码,但是最终的目标需要你自己独自尝试。
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And if you're sharing a particularly decent amount of code, you should definitely submit it as private, or if easier, you can email help at cs50.net.
当你分享了一些相当好的代码量,也可以私下提交，或者更简单点，发邮件到cs50，net寻求帮助。
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So this line or these lines of code up here are arguably constant time steps to say if N is less than 2 in return, that it will always take maybe one step, maybe two steps, some number of fixed CPU cycles.
如果N小于2并返回,那么这些行所对应的代码,通常只需要执行一步，或者两步，具体数字与CPU周期有关。
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