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Let me cluster them because really what I have, sorry, separate them out. I've gone from one problem size eight down to eight problems of size one.
让我把它们聚集起来，因为已经得到我想要的，抱歉，把它们分开来,现在我从一个长度为8的问题,得到了八个长度为1的问题。
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Need to get the base in. Second thing I want to do, I need to get the height, so I'm going to input a value for the height, also as a float, a floating point.
也就是输入底的值，第二件我想要做的，事情就是得到三角形的高,因此我会输入一个值作为三角形的高，同样也是一个浮点数。
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What you said was true, but I wanted something specifically about domination here.
你刚才说的是对的,但我想要得到与优势有关的回答
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If I take the second derivative I get 2, but I want to get a and not 2.
如果我再求二阶导数就能得到2,但我想要a不想得到2
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If I wanted to get full, real division, I should make one of them a float.
如果我想要得到真正的除法答案，我需要把他们之中的一个,变为浮点数类型。
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If I want to get out right now the versions of these things, I can ask what's the value of c p 1 x, and it returns it back out.
你可以在那里看到那些,代表笛卡尔坐标点的东西，如果我想要得到现在，这个类的版本的东西的话。
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Well let's see. My fall back is, I could just do linear search, walk down the list one at a time, just comparing those things. OK. So that's sort of my base. But what if I wanted, you know, how do I want to get to that sorted list? All right?
我只能做线性搜索了,一次遍历一遍列表，一个一个比较，但如果我想要,那怎样得到有序的列表呢？,现在的一个问题是，我们排序之前？
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I've got a number, I want to find the divisors.
我得到了一个数，我想要找到。
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Because in doing that, Python would then have a value that it could pass on into some other part of a computation, and if it wasn't what I wanted, I might be a long ways downstream in the computation before I actually hit some result that makes no sense.
因为如果这样做的话，Python会将,输入的值传递到下面的,一些运算中去，如果这个值的类型不是我想要的，我可能会在得到,一个毫无意义的结果之前,经历一个很长时间的,计算过程。
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I would say, okay, this guy wants me to find a function which reduces to the number a when I take two derivatives, and I know somewhere here, this result, which says that when I take a derivative, I lose a power of t.
出题者想要我找出一个函数,它在经过两次求导后得到数字a,我知道这里的某个地方,这个结论告诉我,我每求一次导,t就降一次幂
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And of course I get out the value I'd like there.
当然我会从这里得到我想要的结果值。
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So in some sets, as long as x has the value I want, it ought to do the right thing.
所以在某些结构中只要x的,只是我想要的我就能得到正确的结果。
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It says if I want to get the length of a segment, going to pass in that instance, it says from that instance, get the start point, that's the thing I just found.
它的意思是如果我想要,得到一个线段的长度，首先要把这个实例传进来，然后对于这个实例，从开始点，取得x坐标，然后通过同样的操作。
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And obviously, when I get to something whose square is equal to x, I've got the answer I want, and I kick it out.
大于x的时候，我已经经过了,想要的答案了，很明显,当我得到一个数的平方等于x的时候。
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