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If its in Cartesian form I'll pass in an x and y and compute what a radius and angle is.
来得到的这个点,我都可以得到这个点的,全部的这种信息。
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where I was going to be able to have a lot of personal attention
这样我就能在这个课程中得到较多的个人关注。
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I could have done this in another way but I am going to just be extra deliberate so I make sure that this copy ends with back slash zero and voila, now, I have a copy.
我可以用另外一种方式来处理,我确保这个拷贝由反斜杠0结尾,那样，现在我得到了一个拷贝。
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I'll let you chase it through, it does work. What I want to look at is, what's the order of growth here?
我会让你们去运行这个方法的，确实能得到正确答案，我想问的是，这个解决问题的方法的增长率是什么？
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That's the intuition I've got when I think about Bernard Williams' second case.
我思考案例二时得到的是这个直觉。
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What we do--I'll show you how they got their number.
现在,我演示一下如何得到这个数字
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By doing it, I got this formula.
这样一来,我就得到了这个式子
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If I drew this altogether and this is one particular nucleic acid, now shown in more detail, all of the carbons of the pentose are shown here, the phosphate is shown, and a base is shown.
如果我把这个放在一起,这个核酸分子,让你们看得到更多细节,戊糖的五个碳都在这儿,磷酸基在这儿,碱基在这儿
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Well, this, I got this my 16th birthday.
这个是我十六岁生日的时候得到的。
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I think it needs to be more important, not problematized, not post-911.
我觉得这个问题应该得到重视，并不是要将其妖魔化，或者恐怖化，像911事件后那样。
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I thought that was a just fabulous program and that generated very board bipartizan support.
我认为这个计划非常成功,而且得到了两党的广泛支持。
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And when I threw those away, I was left once again with a little box, and I could do it again, and again, and again.
剔除之后,我得到了更小的方格,我可以一次一次的重复这个过程
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And I imagine the first person who articulated the question aloud probably met with the response saying, "What a stupid question. Of course things fall down."
我想象第一个人,大声提出这个问题,可能得到这样的回答，多么愚蠢的问题，物体当然下降“
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And if I do that then I can find out the change in enthalpy of this reaction. It's just going to be the heat of formation of these three moles of water, minus the heat of formation of the iron oxide. OK.
我就能得到这个,反应的焓的变化,它就是三摩尔水,的生成热，减去氧化铁的,生成热，好。
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If I want to get out right now the versions of these things, I can ask what's the value of c p 1 x, and it returns it back out.
你可以在那里看到那些,代表笛卡尔坐标点的东西，如果我想要得到现在，这个类的版本的东西的话。
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Since that object is itself a list, what I get is a list of lists.
因为这个对象本身就是个数组，因此我得到了一个包含数组的数组。
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In this case, I'm going to get back the answer 3 F-O-O because the user typed in F-O-O, but wait a minute, what's with this?
假若这样，我得到了答案3,因为用户输入了，等一下，用这个干吗？
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OK, once it gets to the end of that, what's it going to do? It's going to come down here and, oh. What's that doing? Well I cheated when I started. I said, somebody's giving me a perfect square, I'm looking for the square root of it. But suppose 15 I gave this thing 15, and asked it to run.
好，一旦到了循环的最后，程序会去做什么？程序会跳到这里来,噢，这是干什么的？好吧,当我开始的时候我有点小作弊的意思,我说过，我得到了一个完美的平方数,我要求这个数的平方根,但是假设下我得到的数是。
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All right,that's the intuition I've got about the case.
那就是我从这个试验得到的直觉。
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All right. I tried it on 2, I surely didn't expect a precise and exact answer to that but I got something, and if you square this, you'll find the answer kept pretty darn close to 2.
好，我试试求2的平方根,我当然不希望得到一个完全准确的答案了,但是我得到了一个近似值，试试将这个数平方一下,你会发现结果和2相当接近。
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That's the intuition I've got when I think about this case.
那就是我从这个试验中得到的直觉。
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I just want to show you how that comes out.
我现在来告诉你们这个答案怎么得到的
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He said, I'm trying to remember where I got the idea and, he said, I think it probably came from some of our coffee hours at The London School of Economics in the 1920s.
他写到,我尽我所能,追忆当初如何得到的这个概念,也许是20年代,在伦敦政治经济学院,这个概念源于一次咖啡时间
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So I've got one more piece of bad code on this point and this is buggy five dot c. So as a comment on top bug of this file challenges, what is, in fact, the bug.
所以我在这里得到了一块很烂的代码,这个是buggy5，c，所以作为这个文件顶端的注释,那实际上是那个。
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And before we say that the soul view's got the better explanation, we have to ask ourselves, just how much of an explanation is it to say, "Oh I can explain consciousness.
在我们承认,灵魂观点更合理之前,我们必须问问自己,这个观点解释得到底如何,我可以解释意识
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It says if I want to get the length of a segment, going to pass in that instance, it says from that instance, get the start point, that's the thing I just found.
它的意思是如果我想要,得到一个线段的长度，首先要把这个实例传进来，然后对于这个实例，从开始点，取得x坐标，然后通过同样的操作。
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I know this is the right answer, because if I now find the acceleration, I find it's mg divided by m and I get -g as the answer for all bodies.
我知道这个等式是正确的,因为现在如果我要求物体的加速度,用 mg 除以 m,我就得到 -g,这个结果对所有物体都成立
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If you want to know how fast it's moving at a given time, if you want to know the velocity, I just take the derivative of this answer, which is 10-10t.
如果你想知道它在给定时刻的运动有多快,如果你想知道它的速度,我只要对这个式子求导,得到10-10t
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I would say, okay, this guy wants me to find a function which reduces to the number a when I take two derivatives, and I know somewhere here, this result, which says that when I take a derivative, I lose a power of t.
出题者想要我找出一个函数,它在经过两次求导后得到数字a,我知道这里的某个地方,这个结论告诉我,我每求一次导,t就降一次幂
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So what we're going to do is take the equations for those two lines, so here's one of those equations and here's the other one, set the P in those equations equal to X, I've got two equations in one unknown, I'm sorry, I've got one equation and one unknown.
接下来我们只需要,列出这两条线各自的方程,也就是这个方程和这个方程,把方程中的P换成X,我就得到了两个等式和一个未知数,错了,是一个等式和一个未知数
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