So you know from algebra I can't actually solve this. There may be multiple solutions to this. What would I have to do to change my code? And the answer is fortunately not a lot.
我解不出来方程,可能会有多组答案,我需要怎样修改我的代码呢?,很幸运的,答案是不用修改很多。
So, I don't even have to worry because you're not writing this down, so I can just fix it when I post the notes and no one will ever know, except that this is not OpenCourseWare.
所以我甚至不用担心,因为你们不会把这个写下来,所以我可以在我给出讲义的时候再修改,而且不会有人知道,但除非这不是公开课。
So I could get to that object either through this path or through that path, it didn't matter which path I use to modify it, I would see it when I looked at the other. Yes.
另外一条绑定获得这个对象,无论我通过哪个绑定来修改它,我都能在两个绑定中都看到做的改变,是这样的。
But refining in just the right way is going to turn out to be a surprisingly not straightforward matter, at least that's how it seems to me.
但是让人惊讶的是,要正确地修改它,并不是那么直接而简单的,至少在我看来不是。
So I think about these categories have to be considerably revised.
所以我觉得那种划分方法,必须进行大幅修改。
Now, I'm going to add one more amendment.
现在我再稍微修改一下
In this case it says, this is a syntax error, and it's actually highlighting where it came from so I can go back and fix it.
在这个例子中它显示这是个语法错误,并且会高亮显示它的位置,以便于我去修改。
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