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First of all, having read in that value, I can check to see, is it of the right type?
首先，读一下这个值，我们可以来检查看看是不是正确的类型？
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and say, "You've not checked it properly. We are in England, use the English language."
然后说，“你没有正确地检查它，我们在英国，请用英式英语。”
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Well if I-- you know, with let me say it differently. I don't need to worry about how checking is done, it's handled inside of that function.
好，如果你们知道，抱歉，让我们换种说法,我不必担心检查工作,是则会么做的，这是在方法体内部进行的。
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And the last thing we do for any of our structures to check them and figure out are these valid or not valid, are these good Lewis structures is to check the formal charge.
而为了检验任何一个结构是否有效,看它们是不是好的路易斯结构,我们要做的最后一件事就是检查形式电荷。
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You always want to check your signs at the and because it's so easy to get the sign wrong, and I was hoping that it was right here because I wasn't sure, but it turned out to be right.
我们完成计算时，一定要记得检查符号,因为很容易弄错符号，刚才我就不太确定,是否弄错了符号，检查发现没有问题。
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So, let's do a little sanity check now and let's try to demonstrate as much I now claim I'm going to capitalize the copy of the string I just made.
多以，让我们做一个检查,然后做一个演示，现在我声称,我要利用那个字符串的拷贝。
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87 Let's check. Here is sodium plus chlorine. It's 787.
我们检查一下，这是钠加上氯，是。
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If we looked at all 30000, genes that were important in each individual how do you pick out which ones are important for a particular disease?
如果我们检查人体中,所有三万个至关重要的基因,要怎样从中找出,导致某种疾病的特定基因呢
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like the healthcare bills? Just, it's terrible.
我们的健康检查单？想想就知道数目可怕。
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We'll test our hypothesis, or at least examine it again see if it's, in some sense, repeatable.
我们要测试我们的假设或者至少再检查一下,让我们看看它的结果是不是可以接受的。
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Let's check it out. I've written a little bit of a test script here, so if we test cell sort, and I've written this so that it's going to print out what the list is at the end of each round, OK.
我们来检查检查，我写了一个小测试脚本,我写这个脚本来测试单元排序，它能够打印出每一轮结束后,链表的是什么样子的。
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OK. How can we check, for example, if it does or if it doesn't seem reasonable.
我们如何检查呢？举个例子，看它是否合理或者不合理。
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First, I'm going to do a sanity check strlen so we've used string length, strlen, before.
首先，我先做一个检查,我们以前使用过字符串长度函数。
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And so can we do a little sanity check with the simple case here?
对这个简单的例子我们能不能做完整性检查呢？
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And so here do we see we can check for equality with zero.
然后这里我们可以检查与0等价的情况了。
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So I have a little sanity check now.
我们现在做了一个明智的检查。
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So let's do a little sanity check.
让我们做一个明智的检查。
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We learn nothing from examining what is going on down here in n equals one shell.
必须仔细检查不然我们学不到什么的,这里n=1的壳。
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Oh wait a minute, that's a little different than what we did last time, right?
这同我上次做的有点不同了，是么？,上一次我们检查了输入？
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We'll use more sophisticated tools before long, but let's do a little sanity check.
我们不久后将用更多的复杂的工具，但是让我们做一个明智的检查。
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But when you start writing programs, especially when we get to web-based stuff where you want -- to check the user's input -- is it valid, is it an email address, -- and all these different scenarios -- it's actually often useful to be able to just enumerate them or rattle them off using this switching construct instead.
但是当你看是写程序时，特别是当我们,使用基于网络的东西，你想要,检查用户的输入-,它是合法的吗？它是不是一个电子邮箱地址？,所有的这些场景-,实际上它常常是有用的，当你用枚举结构列举它们,或者用它来快速地来说出它们。
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So now, in this case, this code is going to, when we get here, check, and if you haven't seen that strange thing there, that exclamation point in bang computer-ese called a bang, it says x if ANS star ANS is not equal to x, all right?
那么现在，在这个例子中，当我们执行到这里，代码会去检查,如果你没有看到过这个奇怪的东西,这个感叹号在计算机学中被叫做,代码的意思是如果ANS的平方不等于？
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But that merging process only takes N steps, N*log N so that's N times log of N. Now, it's a little tricky to reason through this perhaps the first time, let's just take a very simple example and see if we can do a little sanity check here.
但这个合并过程只需要N步，所以时间复杂度是,第一次对此进行推论可能会有点儿棘手，我们举一个简单的例子,看看我们能否做一些完整性的检查。
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Well, the reason, the way that we can check it is just to see if it's in between our two extreme 1 cases. We know that it has to be more than 1, because even if we had total shielding, 1 we would at least feel is the effective of 1.
好的我们可以检查它的原因和方式是观察,它是否在我们的两种极端案例之间,我们知道它必须大于，因为即使如果我们有完全的屏蔽，我们最小感到的有效值是。
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Now if you look at my derivation here, there's one spot where I could have just stopped and proven my point without going through the whole thing.
如果仔细检查我的推导过程，你会发现其实,我们不用研究整个循环过程,就可以证明我们要证的公式。
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If I come into this code, I'm going to check this branch first, if it's not true, ah, there's a return at the end of that branch. If it is true, I do that, and then I've got a second test. If it's true, return I return, otherwise a return.
但是如果我们看看这里,如果我看这段程序,我会先检查这一部分，如果它是假的，啊，这部分分支结尾有一个。
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Notice in this program I have not checked whether or not the user actually provided input.
就拿这个程序说事吧，我们根本没有检查,用户到底有没有输入。
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And so if incidentally, you're a representative of a student group and the alike and your Google calendar is not -- in here, you can check just by flipping through the various-- we have over 200 calendars right now and you can search through them here.
如果你是一个学生团体的代表,你的Google日历在此不存在,你可以检查其他各种各样的-,目前我们有200多种日历,你可以在它们之中进行查找。
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So again, when we check these, what we want to see is that our z effective falls in between the two extreme cases that we could envision for shielding.
所以当我们再一次检查这些时，我们想看到的是,有效电荷量处于两种极端案例中,这两种极端案例。
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It would definitely be wrong if we were doing this because little sanity check if you just got the single one it means what instead?
如果我们这样做就是错误的,一个小检查,如果你用单个“=“，是什么意思？
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