Once each time. Right? I only do one swap potentially, it-- though not one potentially, each time at the end of the loop I do a swap.

每次循环做一次，对么？我其实,就可能做了一次交换，也许并不是可能，每次循环的结束我都得做一次交换。

麻省理工公开课 - 计算机科学及编程导论课程节选

OK, so what have I done? I just added a little bit more now. I'm now running through a pair of loops. Again notice the encapsulation, that nice abstraction going on, which is what I want. Once I get to this stage though by the way, there might be more than one solution.

我现在运行了一对循环,再一次注意这个封装,抽象得很好，这就是我想要的结果,我按这种方式走到这一步的时候,可能会有多组答案。

麻省理工公开课 - 计算机科学及编程导论课程节选

So first time through the loop, the answer is a. Second time it-sorry, as it enters the loop, at the time it enter exits a the answer is a.

当第一次完成循环的时候，答案是a，第二次，对不起，在第一次进入循环的时候,答案就是。

麻省理工公开课 - 计算机科学及编程导论课程节选

Ah ha, it goes into that accept portion, prints out a message, and goes back around the while loop to say try again. And it's going to keep doing this until I give it something that does serve as a float.

他会说输入一个浮点数，啊哈，它就到了那段处理代码,打印出消息,然后回到while循环让我们再输一次,它会持续这么做直到它接受到一个浮点数。

麻省理工公开课 - 计算机科学及编程导论课程节选

Next time through the loop it goes to a cubed.

然后再一次循环变成a的三次方。

麻省理工公开课 - 计算机科学及编程导论课程节选