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You see that a lot with Nobel prizes, there's usually a nice little scandal, a nice little interesting story behind who else was responsible for the Nobel Prize-worthy discovery.
你们看到很多诺贝尔奖背后，都有一些丑闻，都有一些关于谁还应该得到,诺贝尔奖的小故事。
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When people say,You know,everyone dies alone, you're supposed to be gaining some deep insight into the nature of death.
当人们说，每个人都孤独而死，这应该让你得到对死亡本质的深刻认识。
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Poets are not only due the highest respect imaginable here on earth, Milton's explaining to his dad.
诗人不单止在世上应该得到可能的最高尊重，弥尔顿跟他父亲解释到。
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Three. Good, so everyone that recognized that probably got the right answer of three angular nodes here.
三，很好，那么知道这一点的同学,应该都得到了正确结果,也就是三个角向节点。
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It should have the property that when I add it to anybody, I get the same vector.
它也应该有这种性质,用它加任何矢量,得到的还是原矢量
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So in both cases, no matter what the other person does, she receives a higher payoff from choosing Alpha, so she should choose Alpha.
这两种情况下,无论别人怎么选,她选α总能得到更好的成绩,所以她应该选α
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You could run through a little loop to say keep trying until you get one. But one of the ways I could deal with it is what's shown here.
你可以运行一个小循环来不断地做,直到得到一个输入,但你应该做的是弄明白这里到底要干什么。
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one of the answers we should receive would be: " "It is happiness."
我们应该得到的一个答案是：,“是快乐“
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So, you can imagine, that we'll actually probably have a lot of kinetic energy left over if we put a lot of energy in in the first place.
因此，可以想象，如果我们一开始,就注入大量的能量,那么得到的动能也应该很大。
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So that means if we add up all of the formal charges within the molecule, what we would expect to see is that they sum up to give a net charge of negative 1.
那么这就意味着如果我们把这个分子中,所有的形式电荷加起来，我们应该会看到它们加起来,之后得到的净电荷量为负一。
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And what we have left here is the sulfur, which will also get a pair.
剩下的是硫，它也应该得到一对。
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And once I know that she's going to choose Alpha, it's clear that I should choose Alpha and get 0 rather than Beta and get -3. So I should choose Alpha also.
一旦我意识到她会选α的时候,很显然我应该也选α来得到0单位效用,而不是选β只得到-3,所以我也选α
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I'm going to go there initially, so I can move this over here, so I can get the base part of that over there, I want to put that one there before I put this over here, finally I get to the point where I can move the bottom one over now I've got to be really careful to make sure that I don't cover up the bottom one in the wrong way before I get to the stage where I wish they were posts and there you go.
我要先把其他的放到多余的柱子上，然后把最底下的放到目标柱子上，我要在把除了最底下的圆盘，其他的圆盘挪过来之前,把最下面的圆盘放在这儿,因此我得出了最下面的盘子,应该如何摆放的结论,当我没得到其他盘子的正确摆放位置的时候,要很小心的确认没把错误的盘子,放在最下面的盘子上面。
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At any rate, I don't know for certainty that I'm a harder grader, but I believe that it's the case based on reactions I get when I give the speech that I'm about to give.
不管怎么，虽然不是特确定我评分严格，但相信应该就是这样,根据我每次说这些话时得到的反应来说。
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So certainly part of the problem here, with the reasoning I just gave you-- the reasoning that said I should choose Beta, because if we both reason the same way, we both do better that way-- involves some kind of magical reasoning.
那么说问题就出在了这里,就是之前我们说应该选β的问题,如果我们要都这么想,确实得到更好成绩,但这是有前提的
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And that idea was, we make a guess in the middle, we test it so this is kind of a guess and check, and if the answer was too big, then we knew that we should be looking over here. If it was too small, we knew we should be looking over here, and then we would repeat.
这些有理数是有序排列的,然后我们的想法是,首先在中间取个数作为猜想数，然后对这个猜想数进行验证，如果由猜想数得到的答案太大,我们知道应该跳过，比猜想数大的那个区间，如果太小的话。
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s So, we would actually take an electron out of the s, 3 d 3 4 s 1 which gives us 3 d 3 and then 4 s 1.
轨道，The，s。,因此，我们应该拿走s，轨道上的一个电子，然后得到。
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Same sort of subtraction problem, what do we have for the ionization energy of the 2 s electron?
进行类似的减法运算,得到的，2，s，电子的电离能应该是多大呢？
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That means, when I take two derivatives, I want to get a, then you should know enough calculus to know it has to be something like at^, and half comes from taking two derivatives.
也就是说,当我想求二阶导时,得到了a,你应该有足够的微积分知识,才能知道必须有类似at^的项,而这个1/2则是因为求了两次导数
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Conversely, if you get an answer and it doesn't seem to make sense, then you've got to go back and ask, am I violating some of the assumptions, and here you will find the assumption that the particle had that acceleration a is true as long it's freely falling under gravity but not when you hit the ground.
反过来说,如果你得到一个结果,发现似乎是错的,那么你就应该回过头来问问自己,我是不是违反某些前提了,这个模型中,你就发现,只要质点在重力作用下自由下落,质点具有加速度a的前提是正确的,但是落地后就不成立了
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