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So the average is 30. So the total is 90, the average is 30, am I right so far?
平均数是30,总和是90,平均数是30,这回没错吧
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For instance in the past, we had that silly little program for computing the average of some quizzes and it was actually a pretty bad implementation because I had essentially hard coded in the number of quizzes.
比如在以前，我们做了一个,计算平均数的程序,这是一个相当挫的实现,因为我硬编码了测试的数字。
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we learned that the average number of romantic relationships for people to take positive psychology in 4 years is between zero and one.
我们了解到上积极心理学课的人,在4年里恋爱次数的平均数在0到1之间。
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Let's take the average over all the different years."
那就把每年的收益率求一个平均数吧
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Then you take the average of g and x over g.
之后你会得到一个大于g的平均数。
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The first sentence in the argument was, if the people in the room choose random, then they will choose around 50. That's true.
第一句话是,如果教室里的人随机选择,那平均数会落在50左右,这很对
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I chose 22 because I thought that most people would play the game dividing by two-thirds a couple of times, and give numbers averaging around the low 30's.
我选了22因为我想大多数人在游戏中,可能会多次求平均数的2/3,最后会得出30以下的数
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The average number of sexual partners is between zero and .5.
性伴侣数目的平均数是在0到0。5之间。
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I need to divide it by three to get the average.
我应该先除3得到平均数
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Without showing your neighbor what you're doing, put in the box below a whole number between 1 and a 100 We will calculate the average number chosen in the class.
从1到100之间选择一个号码填到,下面的方框内,不要让你同桌看到,我们会计算全班的平均数
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Right, so to get all the way, good, so to get all the way, thank you So to get all the way to 1, we need a lot.
没错,所以这样一来,很好,所以这样一来,谢谢你,要让平均数到1需要很多条件的
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If people in the room choose randomly between 1 and 100, then the average is going to be around 50 say and two-thirds of 50 is around 33, 33 1/3 actually.
如果大家在1到100之间随机选择,平均数会是50左右,而50的2/3大概是33,确切地说是33 1/3
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So, we should use that, but people in finance resist using that because it's a lower number and when you're advertising your return you want to make it look as big as possible.
所以我们应该用这个指标,但金融界反感使用几何平均,因为它比其他平均数都来得小,他们为自己的收益率做广告时,当然希望数字越大越好
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I thought similar to Chris actually and I also thought that if we got two-thirds and everyone was choosing numbers in between 1 and 100 ends up with 33, would be around the number.
实际上我的想法和克里斯的相近,我也在想我们得选平均数的2/3,每个人都在1到100中选择的话,最后结果可能是33,会接近于平均数的2/3
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So two-thirds of the average is 20.
平均数的2/3是20
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What is their average performance?
平均数代表的是什么
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would have been the winning answer had everyone assumed that the average would have been constantly compounded down to 1, but since a couple of people chose the, I mean not incorrect answers, but the higher averages, then it was pushed up to 13.
如果大家都认为,平均数会一直下降到1的话,1应该是最终的答案,但是由于一部分人选择了,并不是说是错误的,但是却高于平均值的数,就把平均数推高到了13
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We played a game at the very end last time, where each of you chose a number - all of you chose a number - and we said the winner was going to be the person who gets closest to two-thirds of the average in the class.
我们在上节课最后做了一个游戏,你们每个人都选了一个数字,你们所有的人都选择了一个数字,选择的数字最接近全班,平均数的三分之二的人就是赢家
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This is very important,which is why I am doing it: "If we want to know how fast a human being can run, then it is no use to average out the speed of a "good sample" of the population; it is far better to collect Olympic gold medal winners and see how well they can do.
这话非常重要，是我作这个研究的原因：,“如果想知道人类最快能跑多快，那从好的样本中测出平均数是“,没用的;,而应该收集田径类奥运冠军的信息,看他们能跑多快。
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So it turns out that the average in this class, the average choice was about 13 1/3, which means two-thirds of the average was 9.
这个游戏的最终结果,平均数大概是13又1/3,它的2/3是9
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Okay, so the average is 30 and two-thirds of the average is 20.
好,平均数是30,其3/2是20
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So if everyone else reasons that way then everyone in the room would choose a number like 33 or 34, and in that case, the average would be what?
如果其余的每个人都那么想的话,如果每个人都会选择33或者34,那种情况下,平均数会是多少
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Sorry, that two-thirds of the average would be what?
抱歉,平均数的2/3会是多少
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the winner is the person whose number is closest to 2/3 times the average The winner will win $5 minus the difference in pennies between her choice and that two-thirds of the average."
所选数字最接近2/3倍平均数人是赢家,赢家的奖金是5美元减去,所选数和平均数三分之二之差的百分数
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Good, so even if everyone in the number-- everyone in the room didn't choose randomly but they all chose a 100, a very unlikely circumstance, but even if everyone had chosen 100, the highest, the average, sorry, the highest two-thirds of the average could possibly be is 66 2/3, hence 67 would be a pretty good choice in that case.
好的,如果每个人,教室里的每个人不是随机选择数字,而是全选了100,这好像不太可能,但如果每个人真的都选了100,就是最大的书,那平均数,抱歉,平均数的2/3会是66又2/3,此情况下67应该是个不错的选项
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