And then I could also do a Gaussian one here, with the mean of and the standard deviation of volatility divided by 2.
然后我在这里再写一个高斯分布的函数,它的浮动值的平均值和,标准偏差值都除了2。
You try to design actually I'm going to come back to that in a second. It's like you're trying to use a hash function that spread things out pretty evenly. But the places you store into in those lists may have to themselves have a small list in there, and when you go to check something, you may have to do a linear search through the elements in that list.
你尝试着去设计,实际上过会儿我会回头讲解这个问题,类似于你需要用一个哈希函数,非常平均的将物体分发出去,但是在列表中你数据,映射到的地方可能会有自己的一小段列表,当你回头查找数据的时候,你可能需要在那一小段列表中做线性查找。
The answer is I can't. OK, in the simple case of integers I can, but in the case of something more complex like faces or fingerprints or passwords for that matter, it's hard to design a hash function that has completely even distribution, meaning that it takes any input into exactly one output spot.
答案是我不能,好吧,在简单的整数的例子中,我可以做到,但是在一些更复杂的场景中,比如面部,指纹,密码相关的问题中,很难设计一个哈希函数具备完全平均的分配,也就是说,做到对任一输入,可以准确地得到相应的唯一输出,因此在一个哈希问题中。
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