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It is joules per atom. Or, if you multiply by Avogadro's number then you will get joules per mole.
焦耳每个原子，或者，如果乘以,阿伏伽德罗常数你会得到焦耳数每摩尔。
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If it is, in fact, positive, then we're going to go in here, but now notice what we're doing here.
如果这个数实际上是个正数，那么我们就到,这里面来，但是请注意我们在这做了什么。
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All right, so the bonding order, you're correct, should be 2, if we subtract the number of bonding minus anti-bonding electrons and take that in 1/2.
好，你们是对的，键序为，如果我们用成键数,减去反键数除以2。
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On the other hand, if we had a quarter as much venture capital, I think that would be in the sense the world would contract too much.
换句话说，如果资金数是风险资本的四分之一，我想现在订立的合同,太多了。
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suppose I asked you to time a 100 meter spring in the Olympics, but I give you a stopwatch that is measured in units of 15 seconds?
如果我要求你,在奥林匹克数给100米短跑计时，但我会给你一个秒表,它可以测出15秒的大小？
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When you get--this is Rituparna, counting the leaves on a tree-- you can estimate, from a sample, the population expected values.
如果你...像数叶子的睿都巴若那一样,只有部分样本的话,你可以来估计总体均值
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If you have the number of moles and two intensive variables, then you know everything there is to know about the system.
如果你有摩尔数,和两个强度量，你就能知道关于这个系统的一切,关于系统的平衡态的一切。
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Well, if intuitively the problem is the result of dividing an int by an int, surely a solution is: "Don't do that," right?
好的，直观地看,如果那个问题的原因是因为整型数除以整型数的话,无疑有个解决方案是：“不要那样做“，是吗？
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John. -Had John entered, if I've counted correctly, let's pretend I have, John would actually have won this election because John is actually further to the center.
约翰,-让约翰加入,如果我数对了,就当我数对了,约翰将赢得这个选举,因为约翰离中心更近
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So, if we have a high intensity, we're talking about having more photons per second, and it's important to know also what that does not mean.
所以，如果我们有一个高强度，我们就是在讨论每秒钟,有更多的光子数，同样理解它不代表什么,也是很重要的。
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Last time we checked the type and said if it is a float you're okay. If not, carry on.
并且会告之是否是一个浮点数,如果不是继续循环。
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So we can have, if we have the final quantum number m equal plus 1 or minus 1, we're dealing with a p x or a p y orbital.
所以如果我们有,磁量子数ｍ等于正负１,我们讨论的就是ｐｘ或者ｐｙ轨道。
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On the other hand, if the value I'm looking for here- sorry, the value I'm looking for is smaller than the value I see here, I just need to look here. All right?
如果我的目标数比这个值要小呢？,我就在这边找就对了，对不对？,做完了这一步,我可以在下一步做相同的操作，假设我选中了这一分支？
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There are two possibilities. If the answer is yes, then I'm still looking for the answer, what do I want to do? Well, I don't have to do anything other than change the counter.
这就是一个测试，有两种可能的结果，如果结果为是的话，然后我就要继续找寻目标数,我该怎么做呢？好。
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So our last question we ask is what's the total number of photons emitted if we give this given intensity for 60 seconds?
最好的问题是如果我们,按照给定的强度照射60秒,那么总的光子数是多少？
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And, if this quantity is less than zero, the bonding is favorable.
如果这个数小于，能够形成键。
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If you have an experiment and the outcome of the experiment is a number, then a random variable is the number that comes from the experiment.
如果你有一个试验,这个试验的结果是一个数,那么相对应的随机变量,指的就是这个试验结果所对应的那个数
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Well it turns out a bunch of years ago people just decided that if we have the ability to express numbers and we actually care about expressing letters of the alphabet, well we just need some kind of mapping between one and the other, ASCII and so thus was born what's generally called the ASCII.
结果证实，数年前,人们觉得如果我们,有数字表达能力,而我们真正在乎其实是字符的表达，那么我们就需要数字和字符的某种对应关系，于是就有了俗称的。
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So, what we can do instead of talking about the ionization energy, z because that's one of our known quantities, so that we can find z effective.
我们做的事可以代替讨论电离能,因为那是我们知道的量子数之一，那是我们可以解出有效的，如果我们重新排列这个方程。
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So if we're talking about the fourth excited state, and we talk instead about principle quantum numbers, what principle quantum number corresponds to the fourth excited state of a hydrogen atom.
如果我们说的是,第四激发态，我们用,主量子数来描述，哪个主量子数对应了,氢原子的第四激发态？
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He saw that if you take the atomic mass of chlorine, 2 add it to the atomic mass of iodine, divide by two, you get something that is really close to the atomic mass of bromine.
他看到，如果你将氯的原子质量，加上碘的原子质量，除以，得到的数将与,溴的原子质量很接近。
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So I'm first going to look for something that's not in the list, I'm going to see, is minus 1 in this list, so it's going to be at the far end, and if I do that in the basic case, bam.
如果我试试第一种最基本的方法,噢，一下就完成了对不对？,因为这种方法查了下第一个元素，然后发现目标数比较下，因为目标数小于第一个元素。
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Then if I'm looking for the square root of something less than 1, I know it will be in my region, right?
如果我要求平方根的数小于,我就知道我们的答案应该,在0-1这个区间了，对不对？
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No, we can't. Because if l equals 1, we can not have m sub l equal negative 2, right, because the magnetic quantum number only goes from negative l to positive l here.
不行，因为如果ｌ等于１,ｍｌ的值不可能等于－２，对吧，因为磁量子数的值,这时只能从－１到１
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The reason I want to point this out to you is, if we go back up to the kinds of data objects we started with, floats, ints, strings, they actually behave the same way.
我要为大家指出这一点的原因是，如果我们想一下以前讲过的,数据类型的种类，浮点数，整数，字符串，它们实际上有相同的行为方式。
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So there's two different orbitals that can have these three quantum numbers, but if we're talking about electrons, we can also talk about m sub s, so if we have two orbitals, how many electrons can we have total?
所以有两个轨道可以有,这三个量子数，但如果我们讲的是电子，我们还要考虑ｍ小标ｓ,如果我们有两个轨道，一共有多少个电子呢？
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All right, so hopefully if you see any other combination of quantum numbers, for example, if it doesn't quickly come to you how many orbitals you have, you can actually try to write out all the possible orbitals and that should get you started.
所以希望你们如果遇到,任何其它的量子数组合的问题，如果你们不能马上想到有多少个轨道，可以试着先写出所有的轨道,这是个不错的切入点。
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If I wanted to get full, real division, I should make one of them a float.
如果我想要得到真正的除法答案，我需要把他们之中的一个,变为浮点数类型。
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It means anybody using that little function get float doesn't have to worry about what's inside of it. So for example, I decide I want to change the message I print out, I don't have to change the function, I just pass in a different parameter.
这代表着用这个方法去获得浮点数,的任何人都不用担心具体的实现了,例如，如果我想改变下,显示的信息的话，我不必去改变方法，我传个不同的参数就可以了。
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