All right. A good quest-- sorry, a good thought, but in fact, son of a gun.

好吧，一个好的要求-对不起，一个号的思考，但是实际上，这很讨厌。

麻省理工公开课 - 计算机科学及编程导论课程节选

Good question. Actually, I've got to get rid of this candy, so since it was a good question, here you go. Nice catch. Almost. Sorry. OK. No, I'm not. I'm sorry. I thought you had it, and then I've got the wrong glasses on and I realized you didn't, so I will, ah come back to that later.

问得好,事实上我不得不给你这个糖果，因为你问的很好，接好，不错，抱歉，对不起，我以为你接到了，我带错了眼镜而且,我意识到你没带错，所以我会待会再讲。

麻省理工公开课 - 计算机科学及编程导论课程节选

All right, it's so if I looked at it, sorry, IF x is less than y, THEN check to see IF x is less than z, and if that's true, print out x is the smallest.

好，代码是这样的，对不起，是不是x比y小，然后去看看是不是x比z小，如果都为真的话，显示x为最小值。

麻省理工公开课 - 计算机科学及编程导论课程节选

And keep going, until the square of one of those integers is greater than or equal to - sorry, just greater than x. OK, why am I doing that? When I get greater than x, I've gone past the place where I want to be.

如果还是比x小的话，跳到3，这么继续下去,直到一个整数的平方大于或者等于,对不起，是大于x，好,为什么我要这么做呢？,让我得到的整数的平方和。

麻省理工公开课 - 计算机科学及编程导论课程节选

Another way of saying it is, I've actually said, what did I use there, and , It's basically saying there is the first point, there's the second point, add them together and I get that point.

我要去做的是-对不起，再运行一次-好，你可以看到我已经把，这两个点的坐标值加到一块儿了，然后返回了r的值,我会让大家看到我们，实际上得到的是什么，这看起来不错，好,我做了正确的操作。

麻省理工公开课 - 计算机科学及编程导论课程节选