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I get that the best research suggest we don't really have complete redundancy with hemispheres, but suppose that we did.
我知道有实验证明过,我们大脑的多余部分,并不是都分布在左或者右半脑里，但假设多余部分确实分布在半脑里。
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What do you think the error is going to be by failing to recognize that at the end of 6 times 10 to the 23rd I have over-counted some energy?
你们可能会发现，这将会有误差,在6乘以10的23次方的末端,我多余地引入了一些能量？
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OK, that's not so bad. Moving a stack of size 2 if I want to go there, I need to put this one temporarily over here so I can move the bottom one before I move it over.
好，并不那么难，移动上面两个圆盘的话2,我需要把最小的盘子，临时先放到多余的柱子上来,这样才能在把它移过来之前,把最底下的盘子放到目标柱子上。
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All I needed to do was to chip away the excess stone, to get rid of the marble that shouldn't have been there.
我只要凿去多余的石头，只留下有用的。
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I'm going to go there initially, so I can move this over here, so I can get the base part of that over there, I want to put that one there before I put this over here, finally I get to the point where I can move the bottom one over now I've got to be really careful to make sure that I don't cover up the bottom one in the wrong way before I get to the stage where I wish they were posts and there you go.
我要先把其他的放到多余的柱子上，然后把最底下的放到目标柱子上，我要在把除了最底下的圆盘，其他的圆盘挪过来之前,把最下面的圆盘放在这儿,因此我得出了最下面的盘子,应该如何摆放的结论,当我没得到其他盘子的正确摆放位置的时候,要很小心的确认没把错误的盘子,放在最下面的盘子上面。
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I get to the end of the loop, and I actually do a little bit of wasted motion there. And the little bit of wasted motion is, I take the value at i, store it away temporarily, take the value where min index is pointing to, put it back in there, and then swap it around.
我走到了循环的末尾，事实上我做了多余的动作了,有点多余的是我把i的值，临时保存起来了，看看MinIndex指向的值，放回到哪里，然后再交换。
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If I want to move this stack here, I'm going to take a stack of size n minus 1 move it to the spare spot, now I can move the base disk over, and then I'm going to move that stack of size n minus 1 to there. That's literally what I did, OK?
如果我想移动这些圆盘，我先把从n-1个圆盘1,移动到多余的柱子上去，这样我就能把最底下的圆盘放到这儿了，然后再把从n-1个圆盘放到这儿来,这就是确切的我怎么做的对不对？
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