And the third thing I need to decide is how do I combine? You know, point out to you in the binary search case, combination was trivial. The answer to the final search was just the answer all the way up.
第三个问题是我需要决定如何进行合并?,就你们所知的,在二分查找中所打印出来的,合并的过程是非常简单的,最后查询的结果,就是一路上来所以的结果。
So we know we always want to have our systems in as low an energy as possible, so it makes sense that a bond would happen any time we got a lower energy when we combine two atoms, versus when we keep them separate.
我们知道我们总是希望使我们的系统,处于能量尽可能低的状态,因此就应该有化学键产生,一旦我们合并两个原子之后体系的能量变得更低,相较于分开时。
I just kept sub-dividing down until I got really easy problems, and then I combine them back.
我不断的进行子分解,直到得到简单的问题,然后我再把它们合并回去。
I'm just saying, "Take this and put it there and combine i and j."
我只会说,"把这个代入那里,合并 i 和 j"
So, for example, 1s1 again we see hydrogen is 1 s 1, helium we say is 1 s 2, or 1 s squared, 1s2 so instead of writing out the 1 s 1 and the 1 s 2, we just combine it 1s22s1 as 1 s squared, lithium is 1 s 2, 2 s 1.
简化符号所以举例来说,我们又看到氢是,氦是1s2或者1s的平方,所以不是将它写为1s1和1,而是我们将它合并为1s的平方,锂是。
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