• And so you could construct all subsets, check that the weight is less than the weight of the knapsack, and then choose the subset with the maximum value.

    因此你可以构建所有子问题,判断它的重量,是否小于背包的重量,然后选择值最大的子问题。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • The biggest benefit is that you can always go and you know,

    最大的好处就是你可以随时去各地游玩,

    来自世界各地的朋友 - SpeakingMax英语口语达人

  • And when we do that we can see this curve, this probability curve, where we have a maximum probability of finding the electron this far away from the nucleus.

    当我们这样做时,我们可以看到这个曲线,这个概率分布曲线,这里有发现,电子的最大概率。

    麻省理工公开课 - 化学原理课程节选

  • And so what's the biggest possible number you can represent, give or take, with 32 bits?

    所以它可以表示的最大的数值是多少呢,大概是多少?用32位表示?

    哈佛公开课 - 计算机科学课程节选

  • This is the effect that we get, I think, from reading Milton - is this notion that he seems to have had one of the largest memories imaginable and that he's remembered just about everything he's ever read.

    我认为,我们从阅读弥尔顿而得到的,是这样一种说法,即他似乎,拥有我们可以想象的最大容量的记忆,他记下了所有他读过的东西。

    耶鲁公开课 - 弥尔顿课程节选

  • Now, you might look at that formulation, the state of war is one against--of all against all and you might say that such a condition of civil war, of maximum insecurity, of the total breakdown of condition of rules and laws is if anything the state of the exception.

    现在,你可以看一下那个构想,抗一切人的状态,你可能会说这种,内战,最大安全感,法律规范全面崩溃的状态,实质上是一种异常状态。

    耶鲁公开课 - 政治哲学导论课程节选

  • What I did was I differentiated this fairly simple function with respect to q1 and since I want to find a maximum, what I'm going to do is I'm going to set this thing equal to 0.

    只不过是对q1求导了,既然我们要求出最大值,只需要令导数等于0就可以

    耶鲁公开课 - 博弈论课程节选

  • And again, we can define what that most probable radius is, that distance at which we're most likely to find an electron.

    同样的,我们可以定义最可能距离,在这里找到电子的概率最大

    麻省理工公开课 - 化学原理课程节选

  • And basically, what that means is you can actually find an electron anywhere going away from the nucleus, a0 but you're most likely to find that you have the highest probability at a distance of a sub nought, or the Bohr radius.

    它说明,虽然你可以,在任何地方,找到电子,但在距离为,或者波尔半径的地方,找到电子,的概率最大,我说过。

    麻省理工公开课 - 化学原理课程节选

  • So, that's sort of the mathematically how we get to a, but we can also just look at the graph here, because every time we go one wavelength we can see that we're back in a maximum.

    这是就我们得到a的数学,办法,但我们可以直接,从图上看,因为每次我们,经过一个波长,都回到一个最大值。

    麻省理工公开课 - 化学原理课程节选

  • So what we can say is look at each of these separately, so if we start with looking at the 2 p z orbital, the highest probability of finding an electron in the 2 p z orbital, is going to be along this z-axis.

    我们可以来分别看看这些图,首先来看看2pz轨道,在2pz轨道里,找到电子的最大概率,是沿着z轴。

    麻省理工公开课 - 化学原理课程节选

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