So, we'll pick up with that, with some of the solutions and starting to talk about energies on Friday.
会去解薛定谔方程的某个方面,我们在周五,将从一些薛定谔方程的解开始。
This was no Saint Francis with enough time to knock out a few canticles or to preach to the birds or do any of the other endearing things so close to Franny Glass's heart.
圣人弗朗西斯没有足够的时间去,来唱颂歌或者向鸟儿告解或者做任何,其他讨喜的事情,正合弗兰尼的心意。
The power of linearity is F=k1+k2 if I come across f of x, y, z equals k1 plus k2, if it is a linear equation, I don't have to go and solve it all over again.
线性的威力是,一个方程,如果它是个线性方程,那么我就不用再去解他了。
Then, you go to the Math Department and say, "Please tell me what's the answer to this equation?"
然后,你到数学系去问,"请告诉我这个方程的解是什么"
Somebody who's not a math major, tell me how I solve out for the maybe the math majors can't do it actually, it's too simple.
谁不是数学专业的,告诉我们怎么解呀,数学专业的觉得它太简单而不屑去解
So, we just want to appreciate that what we'll be using in this class is, in fact, the solutions to the Schrodinger equation, and just so you can be fully thankful for not having to necessarily solve these as we jump into the solutions and just knowing that they're out there and you'll get to solve it at some point, hopefully, in your careers.
所以,我们仅仅想要鉴别,将会在这门课中用到的,事实上就是薛定谔方程的解,而且你们可以非常欣慰,因为你们没有必要去,解这些方程而是直接用它们的解,并且知道这些解出自那里,希望你们在学习生涯中。
We don't have to worry about how you solve it, but it's problem in mathematics and the answer will be--surprise, it's going to be oscillating back and forth and that'll come out of the wash.
我们没必要去担心这个方程该怎么解,但这个数学问题的答案将会是令人惊讶的,弹簧会来回振荡,问题就迎刃而解了
We don't always want to go and solve the Schrodinger equation, and in fact, once we start talking about molecules, I can imagine none of you, as much as you love math or physics, want to be trying to solve this Schrodinger equation in that case either. So, what Lewis structures allow us to do is over 90% of the time be correct in terms of figuring out what the electron configuration is.
我们并不想每次都去解薛定谔方程,而且实际上,一旦我们开始讨论分子,我可以想象,你们中没有一个人,不管你有多么热爱数学或物理,会想去解这种情况下的薛定谔方程,总之,路易斯结构能让我们,有超过,90%,的概率判断出正确的,电子排布。
So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.
我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来,我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。
How would we go about, I mean I don't want to do it because I'll probably get it wrong, but if I wanted to solve out for this X and the Y, since this is a QR class, let's just talk about it a second.
我们怎么解呢,我的意思是我现在不会去计算,因为我可能会算错,但是如果你真的很想解出X和Y的值,介于这是一节需要快速反应的课,那我们花些时间来探讨一下吧
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