Step three in our Lewis structure rules is to figure out how many electrons we would need in order for every single atom in our molecule to have a full valence shell.

路易斯结构规则的第三步是,找出让分子中每个原子的价壳层,都排满应该需要多少个价电子。

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So as we go down we're now adding electrons to further and further away shells, so what we're going to see is that the atomic radius is going to increase as we're going down the periodic table.

当我们向下走时,我们会将电子加在越来越远的壳层上，因此我们将看到原子半径,将随我们沿周期表向下走而增大。

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s1 Here is 1s atomic. But lithium has 2s1, so I need a 2s atomic orbital here and likewise over here.

这是1s原子，但锂有两层，所以我还需要在这里添加2s轨道,就像那样。

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We're saying the probability of from the nucleus in some very thin shell that we describe by d r.

某一非常薄的壳层dr内,一个原子的概率,你想一个壳层时。

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Whereas for fluorine, fluorine is smaller than f minus is the one that's the outer shell shown here.

而对于氟来说，氟原子更小,与外部壳层在这的负一价氟离子相比。

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So you can imagine, we actually don't need to think of it as a piece of gold foil it might be easier to think of it as a couple of layers of atoms.

所以可以想象,我们不用把它当成一片金箔,只要把它当成是几层原子,所以他所作的就是。

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So here we're talking about v plus 1, so if we were to write it just for the neutral electron itself, we would find that the electron configuration is argon, that's the filled shell in front of it.

这里我们要分析的是正一价的钒离子，因此，我们先写出中性原子的电子排布，可以发现，其原子实是氩原子的电子排布，这些壳层已经被占满了。

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r And what that is the probability of finding an electron in some shell where we define the thickness as d r, some distance, r, from the nucleus.

在某个位置为,厚度为dr的壳层内,找到原子,的概率，我们来考虑下我们这里所说的。

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And when you talk about n for an orbital, it's talking about the shell that shell is kind of what you picture when you think of a classical picture of an atom where you have 1 energy level, the next one is further out, the next one's further away.

当你们谈到，某个轨道的n时，你们说的是壳层，壳层就是,你想象，一个原子,的经典图像时的场景,你有一个能级，下一个再更远的地方，再下一个又更远。

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