I have shown that by taking Avogadro's number of individual ion pairs and putting them all together in a line, the system's energy became more negative.

我推导出了,从每一个离子对中抽出阿伏加德罗常数,再把它们放在一起在一列中，这个系统的能量就变得更负。

麻省理工公开课 - 固态化学导论课程节选

And what I am going to do is say start with this ion, add up the energy associated with the interactions between that ion and everybody else in the row and then multiply it by Avogadro's number, because that is the number of atoms there are in a row.

接下来我要从这一离子开始，加上相互作用的能量，也就是这一离子,和其它所有在这一行的离子之间的能量,再乘以阿伏加德罗常数，因为这是在一行的原子的数量。

麻省理工公开课 - 固态化学导论课程节选

Everyone knows from calculus that if you're trying to find a function about which you know only the derivative, you can always add a constant to one person's answer without changing anything.

学过微积分的人都知道,如果你想根据已知的导数,求出其原函数,你总是可以给某人的答案,随便加一个常数,且不影响结果

耶鲁公开课 - 基础物理课程节选

What I am going to do now is I am going to multiply by N Avogadro and then add Born repulsion.

我接下来要做的是,将其乘以阿伏加德罗常数,再加入Born的排斥作用。

麻省理工公开课 - 固态化学导论课程节选

I got Avogadro's number of these things.

我们得到了阿伏加德罗常数倍的这些东西。

麻省理工公开课 - 固态化学导论课程节选

So let's just multiply that by Avogadro's number.

让我们乘以N，阿伏加德罗常数。

麻省理工公开课 - 固态化学导论课程节选