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Negative 1 plus 0 should add up to negative 1, if in fact, we're correct for the c n anion.
负一加上零应该等于负一，如果是这样，我们对于氰离子的结果就是正确的。
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it's clear that you want to add a vector that looks like that, because then you go from the start of this to the finish of that, you end up at the same point and you get this invisible 0 vector.
显然应该给它加上这样一个矢量,因为从这个矢量的起点指向那个矢量的终点,最终指向的是同一个点,你就得到这个不可见的零矢量
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du external dV minus T surroundings dS is less than zero.
加上压强p，du，plus，p,乘以dV减去环境温度T乘以dS小于零。
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So, du plus p dV is less than zero.
因此，du加上pdV需要小于零。
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q Work is zero. Delta u is w plus q, work plus heat. This is zero, this isn't.
功是零，△U是w加，功加上热量，这个是零。
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I expect that if I add -A to A, I should get the guy who plays the role of 0 in this world, which is the vector of no length.
我希望如果用 -A 加上 A,应该得到一个零矢量,也就是一个没有模长的矢量
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