I want to make one more remark about what I'll be doing in terms of this class.
我想再多弄一次关于,在这个课题上我会明确地做什么的讨论。
Alright, so maybe a little underwhelming and we saw already what this program is going to do but let's just go through this process once before we start doing more interesting things and then we'll come back and at least give you a hint of what some of these syntactic details are doing.
好吧,这个程序也许太平庸了,让人印象不够深刻,我们也知道这个程序是干嘛的,在我们开始更有意思的事情之前,让我们再来讨论一下整个过程后再回来,这些语法细节到底是在做什么呢?,先给你们一点小小的提示。
You don't have to petition the government to do something.
你不必再去请求政府,出面做什么事情。
And again, notice what I've done.
再一次看看我们做了什么。
Another little pop quiz here, and these aren't trick questions necessarily, but if you had to guess what the bigger problem was in the developing world, so let's not just say outside the U.S.
我们再做一个小测试,这不是什么难题,你们猜猜,发展中国家面临最大的问题是什么,我们所说的不是美国以外的国家
So what we can do then is for those schizophrenics that on typical neuleptics A we can actually switch them to the A typical neuleptics and run them under the same experiment again and look at what's happening.
我们接下来要做的是,对于那些服用典型药物的精神病患者,我们让他们转用药物,然后再对他们做相同的试验,来看看有什么变化。
I divide them in half one more time.
我要做什么?,再一次的将这些列表进行分半。
Really there's no work to be done if I am handed all in sorted order so, you know, There's no work to be done if I'm handed all of the arrays in sorted order so, you know, if I demand that you give me this assumption that the cups are already sorted and then I'll sort them for you, I mean, this is kind of a cyclical argument.
如果杯子是有序排列的,那就没必要再对它进行排序了,同样如果给出的序列本身就是有序的,那也不必再做什么,如果给出这样的假设:,杯子已经有序,但仍需要对其进行排序,这像是个循环的论点。
But first I'm going to have, let's look at what fast Fib does and then we'll come back to the next question.
但首先我将会,让我们看看快速fib算法,做了些什么然后,我们再来讨论下一个问题。
It adds x to y and stores it into z. But if someone wants to be a even a little more snarky, what does this program do?
它把x加上y,再把结果存到z中,但是如果有人,想要做的有点不合常理点呢,那这个程序会做什么?
Another way of saying it is, I've actually said, what did I use there, and , It's basically saying there is the first point, there's the second point, add them together and I get that point.
我要去做的是-对不起,再运行一次-好,你可以看到我已经把,这两个点的坐标值加到一块儿了,然后返回了r的值,我会让大家看到我们,实际上得到的是什么,这看起来不错,好,我做了正确的操作。
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