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8 You will see if you get --I think the delta here is 1.78, 8 which is roughly 1.8.
我认为电负性差值应该是1。,约等于1。
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It sets the mean to 0, for s in stocks and then for s in the stocks, it moves it, giving it the bias and the momentum, then it shows the history.
它会让平均值等于，然后，它会改变它们的值，给它一个偏向值和股价势头值，然后它就会显示历史。
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No, we can't. Because if l equals 1, we can not have m sub l equal negative 2, right, because the magnetic quantum number only goes from negative l to positive l here.
不行，因为如果ｌ等于１,ｍｌ的值不可能等于－２，对吧，因为磁量子数的值,这时只能从－１到１
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Then the present value of $1-- The present PDV or PV of $1 = $1/.
一美元的现值...,一美元的现期贴现值或者现值就等于1/
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Both of them now equal what value?
两个变量都等于哪个值？
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I'm going to just put that in, and it's the cosine of the number times i plus sine of the number times j times R.
我要在式子加入这个量,这个式子就等于这个值的余弦乘以 i,加上这个值的正弦乘以 j 再乘以常数 R
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We go to n equals two for a fixed value of Z.
我们对于一个给定的Z值，让n等于。
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We have an interpolation scheme between zero and 273.16 with two values for this quantity, and we have a linear interpolation that defines our temperature scale, our Kelvin temperature scale.
的两个值做线性插值,就得到了开尔文温标,直线的斜率等于水的三相点,也就是这一点处的f的值,再除以273。16，这是这条直线的斜率，这个量，f在三相点处的值。
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What q2 makes this equal to 0 and Katie's answer is solving out the algebra here is that q2 that solves this must be a - c over b.
2为何值时这个算式等于0呢,凯特回答其实就是算出这个的解,即,q2=/b
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PROFESSOR: OK. We can have n 4, l 3, and then, sure, we can have m sub l equal negative 2 if l equals 3 What's the second value of l that we can have?
教授：嗯，我们有ｎ４，ｌ３,然后我们有ｍｌ等于－２，如果ｌ等于３,ｌ可以有的第二个值是多少？
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First, it's pointing to the beginning of the list, which initially might be down here at but after a while, might be part way through. And to that, I simply add a halfway point, and then I check.
列表中间的一个部分了，然后我求出列表的中值点,然后看看该点的值是不是等于目标值，如果是的话就完成了，如果不是的话，如果中位值大于我要找的目标值。
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Well, I kind of ignored the notion of bias 0 by making it 0, so let's give it a big bias here.
我一开始的时候,是让偏向值等于，所以这次让我们设一个比较大的偏向值。
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Knowing that, I'm going to say, OK, how many pigs are there, well that's just how we're, however many I had total, minus that amount, and then I can see, how many legs does that give, and then I can check, that the number of legs that I would get for that solution, is it even equal to the number of legs I started with, ah! Interesting. A return.
它将给我返回头的总数，知道了这些之后我可以说好了,有多少猪呢，无论有多少组鸡的数目，我只要用总数减去那个值,之后我就可以知道一共有多少条腿,然后再把这个值和题目中的腿数相比较，看它是否等于一开始的腿数,啊！真有趣，有一个返回值。
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So, if we think of just an example, 2 we could say that 4 l equals 2, what would be our lowest value of m sub l?
举个例子，如果我们说l等于，那m小标l，最小值是多少？
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So when we talk about p orbitals, it's similar to talking about s orbitals, and the difference lies, and now we have a different value for l, so l equals 1 for a p orbital, and we know if we have l equal 1, we can have three different total orbitals that have sub-shell of l equalling 1.
当我们考虑ｐ轨道时，这和ｓ轨道的情形和相似，不同之处在于ｌ的值不一样，对于ｐ轨道，ｌ等于１,我们知道如果ｌ等于１,我们有３个,不同的轨道。
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For an angular node, we're just talking about what the l value is, so whatever l is equal to is equal to the number of angular nodes you have.
对于角向节点，我们其实就是在讨论l，的值是多少，因此不管，l，的值等于几,它就等于你所有的角向节点的数目。
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So, our next level up that we can go is going to be the n equals 2 energy level, but we also have an l and an m value, 0 so our lowest l is going to be a there.
所以下一个能量,是n等于2的能级，但我们还有l和m的值，所以我们最低的l等于。
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So the value is z is 4, it's what I expect, right?
所以z的值等于？
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is two, 10% it means that if the market goes up 10% in value, the stock tends to go up 20% in value and so on.
当β值等于2时，If，β,表明若市场组合增值，股票价值就增长了20%，以此类推。
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If n = 1, x/n can take on only two values: 0 or 1.
当n=1时,x/n的值只可能等于0和1
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At every point of time your mortgage balance is equal to your mortgage payment times that square bracketed thing, where T is the amount of time you have left.
在每个时间点的抵押贷款余额,都等于每月偿还额乘以,方括号内的值,T是剩余年份数
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So, after the second line for code here char * s1 gets the return value of get string this is what the state of our world looks like.
在第二行之后,这个代码char，*s1，等于GetSting的返回值,这就是它看起来的状态。
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I'm plotting--this is the probability of various values of x/n.
这里是x/n等于各个值的概率
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If you go and work that out, log2 log of two and you have two log two, by math you can show that for the line r series m 2*log2 is equal to two natural log of two, which is 1 1.386 which is greater than one.
如果你把它计算出来，这二者的对数，你会得到2个，通过数学，你会得到第r列，第m个值,等于,也就是1。386，这大于。
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We'll introduce in the next course angular nodes, but today we're just going to be talking about radial nodes, psi and a radial node is a value for r at which psi, and therefore, 0 also the probability psi squared is going to be equal to zero.
将会介绍角节点,但我们今天讲的是，径向节点，径向节点就是指，对于某个r的值,当然，也包括psi的平方，等于,当我们说到s轨道时。
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Let me go ahead and call print F. I'm going to say A equals A and then I need a percent D, backslash, comma A; so this is a little bit of -- more syntax than would be nice, %d but I'm just saying, literally, A equals percent D, and I'm plugging in the value of A for percent D.
我们继续调用printf，我说明A等于,然后我需要%d，反斜杠n，逗号;,所以这个有点--偏向逻辑的，而不偏向美观的，但是我刚说了，字面上，A等于，我用%d插入了A的值。
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And what he came out with when he did some calculations is that there's the radius that he could calculate was equal to this number a sub nought, which is what we call the Bohr radius, and it turns out that the Bohr radius happens to be the radius most probable for a hydrogen atom.
等于这个a0的值,我们叫它波尔半径，而,波尔半径恰好是,最容易，找到电子的地方，我们对波尔模型,不做过多的解释,这是因为。
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It's reasonable because it's meant TMP for temporary purposes just to call it temp or T-M-P for short, X and I can define temp as -- why don't I set it as equal to X, initially, because now that I've stored X in a separate chunk of memory, I can now change its value and then I can say Y gets, not X, but temp, and so now I've actually swapped these values.
这是合理的，因为它是为,暂时的目的，只要叫它Temp或简称它为，我可以定义temp为--为什么我不把它设定为等于，最初的，因为现在我把X存储在一个单独的内存块中,我现在可以改变它的值，然后我说Y等于，不是X，而是temp，所以现在我交换这些值。
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