I want to do this carefully and slowly, and before I even start, let me point out in passing that calculus is not going to help us here.
我要慢点仔细讲这部分,在我开始之前,我需要说明微积分,在这里是用不着的
And I can solve them, and if I solve them out, I'm going to get something like, let me just be careful, I'm going to get something like: 1 minus B S1* is equal to 1, or S1* equals S2* is equal to 1 over .
我们都会解这个方程,如果解完方程,我们会得到,我得仔细点别算错,我们会得到,1-BS1*=1,或S1*=S2*=1/
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