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So, what we get for the disassociation energy for a hydrogen atom is 424 kilojoules per mole.
因此，我们就得到了氢原子,离解能的大小为，424，千焦每摩尔。
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And, a lot of the derivations you will see in physics rely on this being able to model as point charges.
然后，你在物理学中看到的许多东西,都是靠以点电荷为模型得到的。
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That got split in half, and that got split in half until I got to a list of one.
在那里被分成两半，然后在那里被分两半,直到得到长度为一的列表。
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So for example, that might have a formal charge of negative 1, because to some extent it has gained that much electron density that it now has a formal charge that's negative.
比如，可能它的形式电荷为负一，因为在一定程度上它得到了这么多的共用电子密度,那么它现在就有了负的形式电荷。
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But your food shall be the grasses of the field; By the sweat of your brow Shall you get bread to eat" So knowledge or wisdom or perhaps moral freedom seem to come at a very high price.
你也要吃田间的菜蔬;,你必须汗流满面,才得以糊口“,所以，人类为得到智慧，道德自由,付出了极大的代价。
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OK, so here is just an engine like what we've already seen, and I'm going to specify that this is a Carnot engine which is to say all the results that we just derived hold for this case.
这一个热机,跟我们以前见过的差不多，我们把它确定为,卡诺热机,所以我们之前得到的结果都对它适用。
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So I'm going to find for you this result using calculus in a different way.
我将为你们展示,用不同数学方法得到的结果
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I just reran make or GCC does it for me, and now I've got all these errors. Well, let's see.
我刚重新运行了make，或者GCC为我编译了代码，现在我得到了这些错误，好的，让我们看看。
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I put in .9958 for every dollar I got out, so my appreciation of my money is 1/.9958. Subtract that by $1, which is what I put in, and that's how much money I made as a fraction of a dollar.
我投入0.9958美元,得到1美元,我的资产增值为1/0.9958,减去1美元,那是我的投入,这就是每1美元,赚了多少钱
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GDMG the GDMG wanted to do was to send the signal that these people were high potentials, were recognized as such and the Merrill Lynch was willing to invest them in order to increase the retention.
的，And，what，the，head，of,负责人想要,发出信号说明,这些人有很大潜力，他们已经得到认可,美林愿意为他们投资,以增加留职人数。
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Okay, now suppose you are the Oikistes, you've gotten the permission from your city to go forward, and you go to the Delphic Oracle and the Delphic Oracle says fine, by all means, go where you want to go.
好吧,现在假设,你被选为Oikistes,即被选出来建设城邦新殖民地的首领 你得到了向前行进的许可,然后你去了特尔斐神示所,神谕说一切顺利,这意味着,你想去哪都可以
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Let me cluster them because really what I have, sorry, separate them out. I've gone from one problem size eight down to eight problems of size one.
让我把它们聚集起来，因为已经得到我想要的，抱歉，把它们分开来,现在我从一个长度为8的问题,得到了八个长度为1的问题。
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If you go to Denmark and you break a $100 bill, you're going to be given one of these, undoubtedly, the 500 kroner note, which is worth about $75-80, and it has Niels Bohr on it.
如果你去了丹麦，换了100美元，毫无疑问，你会得到其中一个像这样的，500挪威币，约为75-80美元，上面有波尔的头像。
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All around. If you plug in the numbers, you will end up with an uncertainty 15% in the momentum as being on the order of 15%.
所有，如果你把数字都加起来，你将得到一个关于动量的不确定度,约为。
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So that means if we add up all of the formal charges within the molecule, what we would expect to see is that they sum up to give a net charge of negative 1.
那么这就意味着如果我们把这个分子中,所有的形式电荷加起来，我们应该会看到它们加起来,之后得到的净电荷量为负一。
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He offers sacrifice to the deity and receives a blessing.
他为神献身，所以得到恩典。
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At any point on the graph you can take the derivative, which will be tangent to the curve at each point, and its numerical value will be what you can call the instantaneous velocity of that point and you can take the derivative over the derivative and call it the acceleration.
在图上的任意一点,你可以进行求导,得到曲线上每一点的切线斜率,所得到的数值,即为该点处的瞬时速度,然后你再求一次导,得出它的加速度
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If I do this, try and get the 10th element of a list that's only eight long. I get what looks like an error, but it's actually throwing an exception.
如果我来这么做,试着去取长度为8的列表的第十个元素,我貌似能得到一个错误。
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Our goal is to take problems and break them down into these computational steps, these sequence of instructions that'll allow us to capture that process.
我们的目标是得到问题,然后将问题分解为这些计算步骤，这些指令集,可以让我们看到这个过程。
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It's a particle of mass m and momentum p has this energy so you solve for the energy, you get two answers.
一个质量为m,动量为p的粒子,有这么大的能量,你解出能量,得到两个解
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That's clear. If I add them, I'll get a vector parallel to i with lengths Ax + Bx.
这很明显 如果把他们加起来,就得到一个平行于 i,模长为 Ax + Bx 的矢量
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Locally x got bound to 3, 3 I added 1 to it, whoop-dee-doo, 4 I get back a 4. But what's the value of x?
这是我想要的对吧？,在局部程序中x被赋值为，我给它加了1，我得到了？
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First there was the observation by Michelson who back in the late 1880s had done very precise interferal metric measurements of the hydrogen lines and had observed that the 656 nanometer line 3 associated with the transition of n equals 3 to n equals 2 was, in fact, a doublet.
首先是麦克逊,在1880年底的观察,他以公制单位对氢原子的光谱线,作了准确的，无其他因素干扰的，测量,发现当n值由3变为2时,会同时得到波长为656纳米的谱线3,实际上是有两条线。
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And so you can imagine that if you mix these, if you take sodium and you mix it with chlorine you get sodium chloride.
如果将它们混合，以钠和氯反应为例,就会反应得到氯化钠。
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First of all, two parameters. It's OK. All it says is, when I call this, I need to pass in two parameters for this to work. All right? Now, if I want to use that, I'm going to use a second piece of code here, called Barnyard. I'm going Barnyard to read in a couple of values, convert them into integers, and then I'm going to use solve to get a solution out.
注意我得到了什么,第一，两个参数,它的意思就是我调用这个函数，我得给它输入两个参数，明白了吗？,现在如果我要使用它我得用,这里的第二段代码，也叫,我将读入一组值，将它们转化为整型,然后我会用solve得到一个解决方案。
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Again we have the charge of the nucleus on plus 2, +2 but let's say this time the electron now is going to be very, very close to the nucleus.
对于我们的氦原子，我们有一次得到了原子核电荷量为,但是我们说这次电子。
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And the change in energy for this reaction is negative 349 kilojoules per mole.
然后得到这个过程的能量变化为,负的，349，千焦每摩尔。
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So for the bond order we want to take 1/2 of the total number of bonding electrons, so that's going to be 4 minus anti-bonding is 4, so we end up getting a bond order that's equal to 0.
键序等于1/2乘以,总的成键电子数，也就是4，减去反键电子数，也就是4。,所以最后得到键序为0。
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When t is equal to 10,000 years or 10,000 seconds, you're going to find y is some huge negative number.
当t为一万年或一万秒时,我们得到y是一个极大的负数
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