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That means that p1 and -- where I am, the point number 1 and point number 2 were completely arbitrary.
因为1和，两个点是2,陆军上面。
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And the last one was just about 2 months ago up in Oregon.
上一次也就是两个月前在俄勒冈断的。
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So now if I look at my V1 over V2 to the gamma minus 1, that's T2 over T1.
于是把^=中2,的两个温度。
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So a plus two ion means that we're removing two electrons from the atom and the electrons that we're going to remove are always going to be the highest energy electrons.
一个2价正离子,我们要移除的两个电子,我们要移除的两个电子,将会是,最高能量的电子。
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OK, that's not so bad. Moving a stack of size 2 if I want to go there, I need to put this one temporarily over here so I can move the bottom one before I move it over.
好，并不那么难，移动上面两个圆盘的话2,我需要把最小的盘子，临时先放到多余的柱子上来,这样才能在把它移过来之前,把最底下的盘子放到目标柱子上。
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Now, we're not quite there because now we have two copies *b=temp of 2 so the last line of code says *b gets temp.
现在，我们还没有达到目的，因为现在我们有两个2的拷贝,最后一行指明。
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I took my role to sniff that out, and to make sure the president heard 2 and 4 on an important issue, and was able to make the decision himself.
我的作用就是发现这些，保证总统可以听到2和4这两个观点4,在一些重要问题上，然后他能自己做决定。
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Exactly, so ignoring these first two positions which were a bit weird, choosing 2 always gave me 5% more votes than choosing 1, regardless of what the other person chooses.
完全正确,所以忽略前两个立场,因为前两个立场有点古怪,我们选立场2总比1多获得5%的选票,无论对手如何选择
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Do you realize that this is a pair of simultaneous equations in which you can solve for these two unknowns, if you like, in terms of these two knowns and these coefficients, which are like these numbers, 3, 2, 4, and 6?
你们是否发现这其实就是一个方程组,你可以用它来解出这两个未知量,你愿意的话,可以用这两个已知量,和这些系数,比如这些数字,3,2,4和6
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Yeah, you have to take 2 lower divisions
你必须选两个相对较低的分支学科，
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And all we mean by constructive interference is that literally those two waves add together, such as the maxima are now twice as high, and the minima are now twice as low.
相干相长，相干相长也就是,说两个波加在一起，所以最大值变成2倍那么高，最低值变成2倍那么低。
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When we increase the potential between the 2 electrodes that we have in the tube -- we actually split the h 2 into the individual hydrogen atoms, and not only do that, but also excite the atoms.
当我们增大两个电极之间电压,我们有-我们可以把氢气2,分解成单个的氢原子，不仅这样，还能激发原子。
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We started with 6, we only used 2.
我们从六个开始，只用掉了两个。
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or 1 lone pair, 2 lone pair electrons.
或者说一对孤对电子，两个孤对电子。
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Down here, I've just got two things to merge, and then I've got things of size two to merge and then things of size four to merge. But notice a trade off. I have n operations if you like down there of size one.
但是n的大小是不同的，是吗？在这里我们只要合并两个元素,然后是合并长度为2的列表,接下来是合并长度为4的列表,但是观察一下之间的权衡关系。
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s Then we go up to the 2 s, and we have two electrons that we can fill in the 2 s.
然后我们上升至，我们有两个电子,可以填充至2s选择。
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And if we picture those two coming together, we form the h 2 molecule.
如果我们想象它们两个靠近时，我们会形成H2分子。
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Person is a real velvet Elvis fan and needed two copies of this one.
每件东西都有两个，这个人是一个,天鹅绒Elvis爱好者，因此它2个都想要。
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So let's do c p 1 dot y, c p 2 dot y.
这不太好因为，两个地方的值都是一样的，对不对？
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I'll put double crosses for "in the second round" 2 and 9.
我在第二次推理上画两个叉,立场2和9
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If you see a problem that asks you, for example, the third ionization energy versus taking a second electron out of the 2 s in a photoelectron spectroscopy experiment, those are two very different things.
如果你遇到一个题目问你的是，比如说，是第三电离能,还是在光电子能谱实验中从，2，s，轨道中,拿走第二个电子，这可是两个完全不同的问题。
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And actually, if I don't want to clobber, as we say, overwrite the value of my variable, ; I could declare another one and store the return value in Y; Y so now I have two ints in memory; X and Y, 3 one with two, one with three.
实际上，如果你不想彻底清除，像我们说的，覆盖那个变量的值，我可以申明另一个变量Y，并在Y中保存那个返回值;,现在内存中有两个int数，X和，一个的值为2，一个为。
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So, our two glitches we see when we go from the 2 p, or from 2 s to start filling the 2 p, and then we also get another glitch when we've half-filled the 2 p, and now we're adding and having to double up in one of those p orbitals.
因此，我们的看到的两个小偏差，一个是在开始进入，2，p，轨道，或者说在填满，2，s，轨道之后,开始填，2，p，轨道的时候出现的，另一个则是在，2，p，轨道半满之后,开始继续加电子，使得其中一个，p，轨道上的。
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sigma So we'll call this sigma, and it's between two s p 2 hybrid carbon atoms.
我们可以叫它，它在两个sp2杂化碳原子之间。
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You add the two, you get 10 = 5a and you get a = 2.
把两个方程相加,你就会得到 10 = 5a 算出 a = 2
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PROFESSOR: Two. And sigma 2 p y, two electrons here.
教授：两个，那sigma2py，两个。
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So if we're comparing the difference between these 2 now, what you'll notice is that in nitrogen we have all half-filled 2 p orbitals, and now, once we move into oxygen, we actually have to add 1 more electron into 1 of the 2 p orbitals.
那么如果我们来比较下它们两个有什么不同，你会发现氮的，2，p，轨道,都是半满的，现在，我们继续看一下氧，我们不得不在其中一个，2，p，轨道上,再放上一个电子。
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b times. So I've got to go 3 b steps. All right I've got to go through the loop b times I've got three steps each time, and then when I pop out of the loop, I've got two more steps. All right I've got the initiation of answer and the return of it.
好，我一共执行了b次循环,每次循环内部进行了三次基本操作,当跳出循环后还有两个基本操作，因此这个初始的答案就是,2+3b次基本操作,来完成这个循环。
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Well, it looks like it took 1 in this case or it involves-- we can put it another way, merging those two lists involved looking at two numbers, 1, 2, and that's it.
在这种情况下看起来只用了1次-,我们可以从另一个角度看，合并这两个列表涉及到了,2个数字，1，2，就是这样。
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So the reality of the situation is that it's a combination between these 2 structures.
因此实际情况应该是,这两个结构的一种组合。
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