OK, notice we have two inexact differentials and exact differentials. This is a condition.
好,注意到这里面有两个不准确微分量,和一个准确微分量,这是结论。
Yeah, it was a good film. I mean, I don't know how much of it was accurate or not.
它是一部好电影。我的意思是,我不知道有多少内容是准确的。
But the reality that we know from our quantum mechanical model, is that we can't know exactly what the radius is, all we can say is what the probability is of the radius being at certain different points.
我们不可能准确的知道,半径是多少,我们只能说,它在不同半径处,的概率是多少,这是,量子力学。
But odds are it's not sufficient just to get it from the user, I, the human need to be handed whatever this function got from the user in some form.
如果只是从用户,我这里获取,好像有点不太准确,我们得交出,该函数从用户那里得到的一切信息。
Obviously-- and that's a bad way of saying it, I said constant the previous time-- in the linear case, it's subtract by certain amount.
这么描述很不准确,我之前在,线性算法中也说了常数,它是每次减少固定的量。
Yes, I'm not sure how to describe that exactly.
是的,我不确定怎样能准确地描述。
So this is the Uncertainty Principle.
所以这是不准确原理。
You can't see this too well but there's a map of the world here that actually shows you all the individual cases of polio that occurred between this period of August 2007 and, it's cut off on the screen, February of 2008.
你可能看不清这个幻灯片,但是这里有一副世界地图,上面准确的展现了在二零零七年八月到,在屏幕上没有显示出来,是到二零零八年二月之间发生的,所有小儿麻痹症的个案
Well, actually, the first remark is, probably wouldn't be completely accurate to say, to describe these views as saying, " "It's being alive per se."
实际上,第一个评价是,也许这种说法不完全准确,他们把这些观点描述成为,“活着本身“
Those have too many inaccuracies because they're just too old.
太旧了,有许多不准确的地方。
and I asked you to give yourself a percentage rating relative to the rest of the class, then if everybody was accurate, or at least not systematically biased, the number should add up to 50%.
我要你相比于其他同学的表现,给自己一个百分数,如果大家都准确地评价自己,或者说大家都不偏心于自己,那么平均百分数应该是50%的。
This is Pieter Claesz, C-L-A-E-S-Z, probably mispronounced.
这是彼得·格莱兹的作品,C-L-A-E-S-Z,我可能发音不准确
All right. I tried it on 2, I surely didn't expect a precise and exact answer to that but I got something, and if you square this, you'll find the answer kept pretty darn close to 2.
好,我试试求2的平方根,我当然不希望得到一个完全准确的答案了,但是我得到了一个近似值,试试将这个数平方一下,你会发现结果和2相当接近。
Probably I shouldn't have said it's a two-step process 'cause it's a three-step process to actually write and run it, and the third step is just going to be to run it.
也许我不应该说它是个两步完成的程序,准确来讲,应该是三步,前两步--写,第三步--运行。
It says, in either case in general, t of b-- and this is where I'm going to abuse notation a little bit but I can basically bound it by t, 12 steps plus t of b over 2.
我可以用一个,比12+t的数代表,这里有点不准确的地方,具体的步数依赖于奇数偶数,但是你们可以看到在两个case中。
In C,I can exist without being a corpse; or rather,without being alive,as a corpse.
在C阶段,我可以不作为尸体而存在;,准确地说,作为尸体,我是死的。
So essentially, each of these orbitals come from linear combinations of all of the original orbitals, and it's hard to picture exactly how that happens, but one that you can at least start to get an idea is if you think about combining the 2 s and the 2 p z here, which is not quite accurate because of course, we're combining all of them.
本质上,这些轨道每个都来,自原来所有轨道的线性组合,我们很难想象这是怎么发生的,但你们可以至少有个概念,如果你们考虑2s和2pz轨道的结合,这当然是不太准确的,因为我们要把所有的都组合起来。
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