Addition of two signed ints results in a signed int.

两个有符号整数相加的结果是一个有符号的整数。

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Does cast between signed and unsigned int maintain exact bit pattern of variable in memory?

做演员之间签署的和无符号整型变量在内存中保持精确的比特模式？

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If one of the operands is unsigned and the other is a signed int, the expression becomes an unsigned.

如果一个操作数是无符号整数，另外一个操作数是有符号整数，那么表达式的结果就是无符号整数。

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C-89 data types (include signed and unsigned) short, int, long, long long, float, and double.

C- 89数据类型(包括有符号和无符号)short、int、long、long long、float和double。

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C-89 data types (include signed and unsigned) short, int, long, long long, float, and double.

C- 89数据类型(包括有符号和无符号)short、int、long、long long、float和double。

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