It turns out that the Root 1 file system isn't even formatted; it's just 256 MB of null bytes. But the Root 2 file system is golden.
这显示Root1文件系统尚未格式化；它只是256MB的空字节。
If I pick an angle of 60 degrees, these are some numbers like half and root 3 over 2.
要是我选择一个60度的角，这些数就会是二分之一和二分之根号三。
When you'd like to create another template, you can just repeat Step 2 of this section about multiple templates to create another template from the root template.
当您想要创建其他模板的时候，您可以重复这部分关于多个模版从根模版中创建其他模板的步骤2。
The returned serializer in line 2 is a root serializer.
第2行中返回的序列器是一个根序列化器。
Under the root level of the repository is the tags directory (created in Listing 2).
储存库的根级下面是标记目录(在清单2中创建)。
First of all, you need a root element, as shown in Listing 2.
首先，需要一个根元素，如清单2中所示。
This script reads the file contents in step 1, and, in step 2 scans the text for the root element and chops off the beginning so that the first thing seen is the start of the root element.
该脚本在步骤1读取文件的内容，在步骤2扫描文本寻找根元素并去掉开始部分，以便让人第一眼就能看到根元素。
Figure 2 shows a snapshot of a root volume.
图2显示了根卷的快照。
First, notice the DN of the root node in Figure 2.
首先，注意图2中根节点的DN。
You can see from Listing 2 that the root tag contains an tag that belongs to the cxfse namespace.
您可以从清单2中看到根标记包含一个属于cxfse命名空间的标记。
Note that the root tag in Listing 2 is, which is part of Spring's XML namespace.
请注意清单2上的根标记是，是Spring的XML命名空间的一部分。
Now repeat the last few steps to create the Virtual Portal 2 content root with a different theme and two similar pages.
现在重复最后几步以创建包含不同主题和两个相似页面的VirtualPortal2上下文根。
However, in the root directory you'll see one new file that identifies this project as a plug-in: ShortenurlGrailsPlugin.groovy. Listing 2 shows a snippet.
但是，根目录中有一个文件将这个项目识别为一个插件：ShortenurlGrailsPlugin . groovy。
If I make it four times shorter-- l 2 the square root of four is two.
如果缩小4倍-,缩小4倍-，l，four，times，shorter--,4的平方根是。
Change PCI Device Boot Priority to the adapter your root file system disk is using (as in Figure 2 below), if your Linux is installed on a local Planar SAS disk.
如果您的Linux安装在本地PlanarSAS磁盘中，请将PCIDeviceBootPriority更改为根文件系统磁盘正在使用的适配器(如下面的图2所示)。
Create alternative child Workspaces 1, 2... n, (and so on) from the root Workspace.
从根工作区那里创建替代性的子工作区1,2…n(等等)。
If you are near Earth in orbit, you are eight kilometers per second, and eight times the square root of two 2 is exactly that 11.2.
如果你在轨道接近，地球，那是8千米每秒，8乘以2平方根，正好是11。
If, however, you're in a static method, you have to get the root node and provide the package yourself, as shown in Listing 2.
但是，如果您使用的是静态方法，您就必须得到根节点并自己提供包，如清单2所示。
The example schema in Listing 2 defines two elements at the root level.
清单2中的例子模式在根层次定义了两个元素。
For example, you can be logged as root on console 1, and logged in as joeuser on console 2.
例如，您可能在控制台1中以root身份登录，而在控制台2中以joeuser身份登录。
Figure 2 shows the discovery chain from the root services document to the service descriptors, via the service Providers Catalog.
图2显示了通过ServiceProvidersCatalog从根服务文件到服务描述器的发现链。
In the next window, browse for the archive file you have downloaded, RCP_Files.zip, and make sure the root node is selected as shown in figure 2.
在下一个窗口中，浏览到已下载的归档文件rcp _ Files . zip，并确保已选择根节点，如图2所示。
Gotcha 2: Establishing the root volume group.
陷阱2：建立根卷组。
Take Pamela Root, who recently became the poster child for permissive parents after she and her 2-year-old son were kicked off a Southwest Airlines flight.
就拿PamelaRoot来说，她最近成为宽容型家长的典范，这发生在Pamela和她那两岁的儿子被西南航空踢下飞机之后。
The period, which is 2 pi times the square root of l over g, if you substitute in your length of 5.1 meters, you will find 4.57 seconds.
周期，等于2π,乘以l/g的平方根，如果把长度为5。1米,代入，会得到4。57秒。
t1/t2 2 would be the square root of h1 divided by h2 That is the dimensional analysis argument h1/h2 that we have there.
也是这样2，And，so，the，time，t1，divided，by，t2,通过之前的量纲分析得到2,它等于,根号下。
The snapshot in Figure 2 highlights a memory leak (String object is leaking), along with the leak's container type (Vector object), and root (TestThreeTierQueue object).
图2中的截图高亮度标示了一个内存泄漏(字符串对象正在泄漏)，连同泄漏的包装形态(矢量对象)和根(TestThreeTierQueue对象)。
I take the square root, 2 I multiply by two.
取平方根，乘以。
How can such a simple test fail? The root cause appears in Figure 2?
这样一个简单的测试怎么会失败？
The length of the diagonal side will be the square root of 2. This diagonal will be used to construct the next square root by employing a similar method.
对角线的长度是2的平方根。应用类似的方法，这个对角线会被用来构造下一个平方根。
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