• It continues until no COBOL program is active in the execution stack for any of the threads.

    这种情况将一直持续下去直到任何线程执行堆栈再也没有活动COBOL程序

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  • The number of threads in the group should be no larger than the depth of the deepest lock hierarchy possible in the system.

    线程数量应该大于系统最深层次结构的深度

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  • The same pinning of threads with larger packets seems to provide less advantage, but no obvious disadvantage compared to the original Suggestions from the WebSphere MQ Low Latency Messaging team.

    WebSphereMQLowLatencyMessaging团队原始建议相比具有较大数据包线程相同固定没有什么优势但是同样也没有什么明显缺点

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  • Note that all the methods, even get(), need to be synchronized for the class to be thread-safe, to ensure that no updates are lost, and that all threads see the most recent value of the counter.

    注意所有方法甚至需要同步get(),使成为线程安全类,从而确保没有任何更新信息丢失,所有线程看到计数器的最新

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  • And remember, thanks to DWR's exploitation of Jetty Continuations, no threads are tied up on the server while the client is waiting for a new event to arrive.

    记住,正是由于DWR使用了JettyContinuations客户机等待事件到来时不会占用服务器上面的线程

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  • Creating 100,000 weightless threads is no problem on an older Windows 98 Pentium II laptop with only 64 MB of memory (at one million threads, long disk churning occurs).

    比较老只有64MB内存Windows 98Pentiumii上型电脑上创建100,000个轻便线程轻而易举的(如果达到了一百万个线程,就会出现长时间磁盘“猛转”)。

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  • To make better use of CPU time, we can create a pool of NHRTs to process the data. By maintaining a pool of running threads, we have no thread startup and shutdown overhead when running.

    更好利用CPU时间我们可以创建nhrt处理数据通过维护一个运行线程池,运行的时候存在任何线程启动停止开销了

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  • Instead you get entirely different concurrent programming models that include no mention of threads or locks.

    相反,它提供线程锁无关的、完全不同并发编程模型

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  • This shows that there were plenty of free connections available and no threads were waiting for a connection, which produces much faster response times.

    表明大量空闲连接可用没有线程等待连接从而实现更快响应速度。

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  • Ideally no two threads can try to modify the same piece of data at the same time, dirty reads are not possible, and deadlocks are automatically detected and handled.

    理想情况下多个线程不能同时访问同一数据读将不复存在,死则会自动监测处理

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  • The number of worker threads is three times your number of CPUs, but it's no less than 5 and no larger than 30.

    工作线程数量CPU数量的但是小于5大于30

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  • Because the TimerCallback function gets called on a worker thread, there are no skipped beats (assuming the availability of worker threads).

    因为TimerCallback功能也是工作者线程上被调用,没有一个跳动跳过(假设有工作者线程可用)。

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  • Finally, I walked though each tag in my list of tags, obtained the tweets, and printed them out. Because no threads were used, this code executes each search serially, as shown in Figure 1.

    最后历了标记列表中的每个标记获取tweets它们打印出来

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  • Yes it is a bad practice when you put no upper bound on the number of threads (or generally resources).

    是的一个糟糕练习线程数量没有上限(一般参考资料)。

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  • If the internal state cannot change, there is no chance for different threads to see inconsistent views of the data. Immutable types can be exported from your objects safely.

    如果内部状态不能改变那么对于不同线程来说没有机会看到这个数据不同值。

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  • There is currently no cure but there are several very promising threads of research underway that could lead to treatment, of which this is one.

    目前没有治愈几个非常有希望线程正在进行的研究可能导致治疗其中其中之一

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  • What if we had not only a pool of hardware resources hundreds wide that could handle thousands of threads in flight at a time with no software overhead?

    如果我们已经不仅一个游泳池硬件资源数百广泛可以处理数千线程飞行时间没有软件开销

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  • If a thread is in upgradeable mode, and there are no threads waiting to enter write mode, any number of other threads can enter read mode, even if there are threads waiting to enter upgradeable mode.

    如果一个线程处于可升级模式并且没有任何线程等待进入模式,那么任意数量线程可以进入读模式,即使有线程在等待进入可升级读模式。

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  • In a multithreaded scenario using IOCPs, the control flow of a thread function is not straightforward, because there is no relationship between threads and communications.

    多线程的情况下使用IOCPs控制流动一个线程函数不是简单的因为没有任何关系线程通信。

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  • Is equivalent to a number of threads at the same time on a map data changes, there will be no memory conflict, what is the hidden problem?

    难道就只有我一个觉得不会出错么?多线程修改数据只要不是同一个地方并不需要锁,楼主只要关键不变不增不减取出值修改应该没问题的。

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  • Is equivalent to a number of threads at the same time on a map data changes, there will be no memory conflict, what is the hidden problem?

    难道就只有我一个觉得不会出错么?多线程修改数据只要不是同一个地方并不需要锁,楼主只要关键不变不增不减取出值修改应该没问题的。

    youdao

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