Because the positive side of C1 cannot instantly change its polarity, it pulls low and slowly charges up again through the internal pullup resistor of the input.
而C1的正向不能立即改变极性，其被拉低并通过输入的内部上拉电阻，缓慢的再次充电。
Because the positive side of C1 cannot instantly change its polarity, it pulls low and slowly charges up again through the internal pullup resistor of the input.
而C1的正向不能立即改变极性，其被拉低并通过输入的内部上拉电阻，缓慢的再次充电。
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