That is, there isn't actually any type called InputIterator: when you call find, the compiler substitutes the actual type of the arguments for the formal type parameters InputIterator and t.
也就是说,没有实际的类型InputIterator:当你调用find时,编译器会把他们替换成正式的类型。
That is, there isn't actually any type called InputIterator: when you call find, the compiler substitutes the actual type of the arguments for the formal type parameters InputIterator and t.
也就是说,没有实际的类型InputIterator:当你调用find时,编译器会把他们替换成正式的类型。
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