N 2004, bank of America hires a research firm to work out how they can get more people to open bank accounts, and more money deposited in these accounts.
2004年,美国银行聘请了一家调查公司,以了解如何才能让人们开设银行帐户,以及存入更多的现金。
Multiply them to get "n = p*q." Next, you pick a small public exponent "e" which is the "encryption exponent" and a specially crafted inverse of "e" called "d" as the "decryption exponent."
接下来,取一个较小的“e”作为指数,它用作“加密指数”,而对e的进行特殊的逆反函数计算所得到的“d”作为“解密指数”。
So instead you'd have to maybe if you start with wavelength, go over there, and then figure out velocity and do something more like kinetic energy equals 1/2 n b squared to get there.
这时你要先从波长开始,到这,然后算出速度,然后像动能等于1/2nb平方得到这。
I've addressed the problem of reusability above, but I still need to get rid of that N-to-1 dependency.
我在上面解决了重用性的问题,但是仍然需要避免n对一的依赖关系。
The aim is to get something like SSH -n host whoami to work without being asked for a password.
这样做的目的是能够不需询问密码就可以执行ssh -nhostwhoami这样的命令。
We'll get to discussing that, but what I want to point out here again is the fact that instead of just being dependent on n, the energy level is dependent on both n and l.
我们将要讨论它,但是我想指出的是事实上能级不只是与n有关,而是与n和l都有关系,而且n不再是。
So I have n operations log n times, n log n there we go, n log n. Took us a long time to get there, but it's a nice algorithm to have.
所以我log,n遍的n次操作,就得到了,虽然花了不少时间得到了这个结论。
So, it would be a good question to ask n why are we limited clearly there's this relationship between l and n, and we can't get any higher than n equals one.
那我们要问了,为什么我们被限制了,很明显,l和,有关系,为什么不能取到,n-1更大的值。
Through controlling an N-bit accumulator and then get its highest bit to generate the programmable clock.
通过控制一个N位累加器累加,取其最高位,即可得到可编程时钟源。
There is no fixed recipe in approaching metering in all kinds of situations. It's a mix-n-match of different techniques - all used to make sure I get optimum exposure for my images.
当然因为情况多种多样,不可能有一种固定方法能适用于所有的情况。一般需要多种技术进行组合以取得最好的曝光。
The first thing I had to do when I arrived in Spain was to get something called an N.
到达西班牙我必须要做的第一件事就是拿到一个叫做N。
The formula for Q(n) is tough to understand and the author is counting on your diligence, persistence, and/or background here to get you through.
的公式确实很难理解,作者也是像你一样坚持不懈的计算和推导中才做到。
I would post a link but my comment will probably get scrubbed by this Is r ae l friendly outfit. a simple google search will reveal the truth about our"ally" n her history of selling secrets to China.
我将会发一个链接,但我的评论可能会被屏蔽,通过简单的谷歌搜索将揭示我们的“盟友”出卖秘密的真相。
So if I start off with a list of length n, how many times can I divide it by 2, until I get to something no more than two left?
我能够除以多少次2呢?,直到我得到的长度不超过2么?,对数次,对吧?就像刚才那位同学说的那样?
Something n**ensical because it's an election year and neither wants the other to get the upper hand… on Olympic uniforms.
有些事是无意义的,因为今年是个选举年,哪一方都不希望对方在奥运制服问题上获得更多民众支持。
'You have to take care of business, ' he said. 'Get to practice (Saturday) and work on things that we want to adjust or get better at and get ready to rock 'n roll on Sunday.
“你必须注意现实,”他说,“多多练球(星期六),调整到最佳状态,全力应战星期日的比赛。”
Master the one-of-a-kind, touch-n-drag Swing Meter and get visual feedback to achieve the perfect swing!
游戏的操作使用了触摸拖曳的方式,并且使用视觉回馈,以实现完美的挥杆!
As transistors get smaller, however, laying down n-type and p-type materials in proximity gets harder, thanks once again to fluctuations in the concentrations of dopants.
然而,晶体管越小,制造PN结的难度就越大,这也是受到了掺入元素浓度波动的影响。
Methods To avoid floating point overflow, we calculate the input value according to the maximum of floating-point number and get corresponding integration step at a given level N.
方法为了避免浮点数溢出,我们由浮点的最大值作为输入参数,然后根据积分级数N计算出积分步长。
N. Then get off at the first stop and ask around for directions. Someone should be able to help you.
线,然后于第一站下车,再向别人问问方向,应该有人能帮你。
I had been trying to get my friend Mike-a rock 'n roll fan-interested in classical music.
我一直设法让我朋友迈克——一个摇滚迷- - - - - -对古典音乐感兴趣。
If you cut away the serifs, also on the inner side of the 'u', the white space inside the 'u' will get bigger then the white space inside the 'n'. This has to be optically corrected.
当你切除了内部的衬线之后,内部的白空间就会比“n”的要大,所以必须进行视觉上的微调。
If you cut away the serifs, also on the inner side of the 'u', the white space inside the 'u' will get bigger then the white space inside the 'n'. This has to be optically corrected.
当你切除了内部的衬线之后,内部的白空间就会比“n”的要大,所以必须进行视觉上的微调。
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