I have already added the union-fs module a while ago, which was a major hurdle to overcome," notes Andrew.
在不久之前,我们刚刚添加了 union-fs模块,这是我们需要克服的一个主要障碍。
This holds for acceleration down Fs=m and so I get F of s equals m times g minus a.
取得向下加速度,因此。
Brian : On the whole quite disappointing really. I got three Fs, two Ds and a C. But I did get one A!
布莱恩: 大致上很失望,我只拿到三个F、两个D和一个C,但我也拿到一个A!
Brian : On the whole quite disappointing really. I got three Fs, two Ds and a C. But I did get one A!
布莱恩: 大致上很失望,我只拿到三个F、两个D和一个C,但我也拿到一个A!
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