• Update firmware for DS4500 and EXP 710 drawers.

    更新ds4500EXP 710固件

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  • If have work exp, encourage to submit application.

    如果工作经验鼓励申请

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  • Exp and write that three times for each of these three.

    当然没有必要种构型连写

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  • Exponential (log, log2, log10, exp, exp2, exp10, SQRT, cur).

    指数函数(loglog2log10expexp2exp10sqrtcur)。

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  • Whoever strikes the finishing blow in battle receives the most EXP.

    战斗中给予对方最后一击,谁将获得更多的EXP

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  • Accurate - hits more often; gives 4 exp to Attack per damage point.

    准确命中较多4实验攻击伤害

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  • Since exp(i*pi)=-1, CPhase(pi,x) will flip the sign of the |1> component.

    由于exp(i*pi)=-1CPhase(pi,x) |1>分量符号取反。

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  • In the Arena, you can now obtain EXP and Gold at the cost of Fatigue.

    新增决斗场中消耗疲劳获得金币奖励系统。

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  • EXP are divided equally among all characters participating in battle.

    EXP将会平均分配给参加战斗的所有角色

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  • Exp: In terms of memory requirements, there is generally no difference.

    在占用(需求)内存方面通常没有什么不同

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  • You gain EXP for the damage you inflict on enemies, even if you run away.

    可以从给予敌人伤害得到经验,即便是逃跑了也会得到。

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  • Import (imp) and export (exp) can be used to perform logical import and export.

    Import (imp)export (exp)用于执行逻辑导入导出

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  • Temporarily Increase the exp gain from each monster. Can be cast without a party.

    临时增加每个怪物获得经验值。即使组队也发挥效果。

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  • Defensive - increases the chance to block; gives 4 exp to Defense per damage point.

    防御-增加机会为了使实验4防御损坏

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  • Aggressive - stronger but slightly slower; gives 4 exp to Strength per damage point.

    进攻强大略为放缓实验实力4伤害

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  • the amplitudes for base states where x is |1> are multiplied by exp(i*a)=cos(a)+i*sin(a).

    x |1>基态振幅上了exp(i*a)=cos(a)+i*sin(a)。

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  • Defeating enemies by physical attacks rather than magical attacks gives you more EXP.

    物理攻击打败敌人得到的经验用魔法攻击打败得到的

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  • Exp debt and Exp loss is really just the same thing, except you can't lose your level.

    经验债务经验损失除了其实一样

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  • Sound education background with min. 2 yrs. exp of yarn selling or other relative selling.

    良好的教育背景及至少2毛纱销售其它相关销售工作经验

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  • Pi So as we've written it, we've got Pi of Ei exp is proportional to e to the minus Ei over kT.

    我们的一样,我们得到,正比于

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  • Requirement: Good English proficiency, Good oral English, Relevent working exp is not required.

    要求英语熟练口语能力要求工作经验

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  • It contains a nested loop that calls exp , cos , and sin , followed by a loop that calls sin and SQRT .

    包含了嵌套循环循环会调用expcos以及sin接下来是一个调用sinsqrt的循环。

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  • The running program will evaluate the expression in Listing 1 twice, with the $exp variable set to and .

    运行程序清单1 中的表达式进行二次求值,其中 $exp变量分别被设置

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  • The running program will evaluate the expression in Listing 1 twice, with the $exp variable set to and .

    运行程序清单1 中的表达式进行二次求值,其中 $exp变量分别被设置

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