• A final advantage of some (though not all) native XML databases is worth mentioning. They can retrieve the original, unparsed document, character-per-character or even byte-per-byte.

    一些(不是全部)原生XML数据库带来的最后一个优点也值得一提,即能够逐字符甚至逐字节地检索原始的未解析文档。

    youdao

  • Even though an object is a single value, we've turned it into a set of fixed-length byte arrays.

    即使一个对象只有一个值,我们也要将它转换为一组固定长度的字节数组。

    youdao

  • You can even load binary classes directly from byte arrays or streams, and create new classes from scratch.

    甚至可以直接从字节数组或者流中装载二进制类,以及从头开始创建新类。

    youdao

  • To load a value which crosses a 16-byte boundary is even more difficult, as you would actually have to load it into two registers, shift them, and then mask and combine them.

    要加载跨越16字节边界的值会十分困难,因为必须要将其存储到两个寄存器,进行移位然后再对它们进行掩码和组合。

    youdao

  • If you use the File Transfer Protocol [FTP] or utilities such as rcp or scp, complete files will be sent, even if just one byte has changed.

    (如果使用FileTransferProtocol [FTP]或rcp和scp等实用程序,那么即使只修改了一个字节,也会发送完整的文件)。

    youdao

  • The program does not even have to be explicitly coded to the current multi-byte encoding.

    这甚至不需要程序被明确的编码成当前的多字节编码。

    youdao

  • If loaded by different class loaders, two classes with the same name, even the same package name, are treated as distinct — even if, in fact, they are byte-for-byte the same class.

    即使两个实例的类名字一样,甚至包名也一样,更甚至于每一个字节都是一样的,但是如果他们被不同的类加载器加载,他们也会被当着是不同的实例。

    youdao

  • Storing such values is even more difficult, so it is best to never use values that cross 16-byte boundaries.

    存储这样的值则更为困难,所以如果可能,最好永远不要使用跨16字节边界的值。

    youdao

  • Since all registers on the SPU are 16-bytes long, this will load a full 16-byte quadword into the register, even though you are only really concerned with the first 4 bytes of it.

    因为所有SPU上的寄存器都是 16字节长,因而这会将整个 16 字节的四字加载进寄存器,而我们所关心的只是它的前4 个字节。

    youdao

  • The latter three cache and optimize the byte code, providing for even greater speedups.

    后三类加速器能够缓存和优化字节码,这为系统提供了更多的速度提升。

    youdao

  • Count the number of ones in each byte of the 8-byte block; if the number of ones is even, make it odd by setting the least significant bit to one.

    统计8字节块中每字节中的1的个数,如果1的个数为偶数,那么就设置最低位为1使它成为奇数。

    youdao

  • No, the application should care about the conversion itself. However, UDT does work between different platforms even with different byte orders.

    不,应用程序应该自己关心这个转换。不过,UDT可以在不同平台间的不同字节顺序情况下正常工作。

    youdao

  • However, UDT does work between different platforms even with different byte orders.

    不过,UDT可以在不同平台间的不同字节顺序情况下正常工作。

    youdao

  • However, UDT does work between different platforms even with different byte orders.

    不过,UDT可以在不同平台间的不同字节顺序情况下正常工作。

    youdao

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