由于两份可执行映像各自的静态数据成员并未同步，这个行为就可能导致访问违例，或者数据看起来似乎丢失或被破坏了。
Since the static data members in the executable images arenot in sync, this action could result in an access violation or data may appearto be lost or corrupted.
由于两份可执行映像各自的静态数据成员并未同步，这个行为就可能导致访问违例，或者数据看起来似乎丢失或被破坏了。
Since the static data members in the executable images arenot in sync, this action could result in an access violation or data may appearto be lost or corrupted.
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