Regan推测这个特殊数字的麻烦之处在于它是“最大的次法线双精度浮点数”。
Regan speculated that this particular number is troublesome because it is the "largest subnormal double-precision floating-point number."
传回小于或等于指定的双精度浮点数的最大整数。
Returns the largest integer less than or equal to the specified double-precision floating-point number.
方法为了避免浮点数溢出，我们由浮点的最大值作为输入参数，然后根据积分级数N计算出积分步长。
Methods To avoid floating point overflow, we calculate the input value according to the maximum of floating-point number and get corresponding integration step at a given level N.
方法为了避免浮点数溢出，我们由浮点的最大值作为输入参数，然后根据积分级数N计算出积分步长。
Methods To avoid floating point overflow, we calculate the input value according to the maximum of floating-point number and get corresponding integration step at a given level N.
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