如果既没有根也没有指针指向链表，那么你的数据就丢失在内存中了。
If there is no root or a pointer pointing to any part of the list then your data is lost in memory.
在什么地方namestr与其它地址数值一起被编写，从而丢失分配在main() 中的最后一个内存指针，最终导致渗漏吗？
Where exactly does namestr get written with another address value, and thereby lose the last pointer to memory allocated in main(), causing the leak?
当strdup在foo中被调用，这个namestr变量值就会被覆写，从而丢失main中内存分配的指针，导致渗漏。
When strdup is called in foo , the namestr variable value is overwritten, thereby losing the pointer to the memory allocated in main , and that causes the leak.
明显丢失或“内存泄漏”：最坏的结果是某些块已没有指针指向，却还能被发现。
Definitely lost, or "leaked" : Theworst outcome is that no pointer to the block can be found.
明显丢失或“内存泄漏”：最坏的结果是某些块已没有指针指向，却还能被发现。
Definitely lost, or "leaked" : Theworst outcome is that no pointer to the block can be found.
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