我们可以用叫做，键序的概念来弄明白它，键序等于1/2乘以成键电子，数目减去反键电子数目。
The way that we can figure this out is using something called bond order , and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.
s和1s上两个电子组成的键合电子成椭圆形,这是成键，这是反键电子，这些是刚刚已经画过的能级,我也给你们画了。
s plus 1s gives you this oval ellipsoid which is the bonding, and here are the antibonding, and then these are the energy levels that I have been drawing for you.
因为这样，反键轨道被堆积了，这两个电子都填到各自的反键轨道。
And because of the way those antibonding orbitals are stacked, the two electrons go one each into those antibonding.
同样的，这是反键轨道，你们看到当你有反键轨道的时候，两个原子核中间的电子密度更小了。
So again, this is an anti-bonding orbital, and what you see is that there is now less electron density between the two nuclei than there was when you had non-bonding.
所以你可以看到这是不成键的，它甚至比不成键还糟糕，它是反键，因为我们实际上是去掉了，两个原子核之间的电子。
So you can see that this is non-bonding, this is even worse than non-bonding, it's anti-bonding, because we're actually getting rid of electron density between the two nuclei.
所以你可以看到这是不成键的，它甚至比不成键还糟糕，它是反键，因为我们实际上是去掉了，两个原子核之间的电子。
So you can see that this is non-bonding, this is even worse than non-bonding, it's anti-bonding, because we're actually getting rid of electron density between the two nuclei.
应用推荐