• 最后讨论代数之间关系,并求出函数展开式系数之间转换矩阵

    By using discussing the relationship of two-kinds of algebra, the conversion matrix of expansion coefficients are derived.

    youdao

  • 此法提供了推导正交坐标系下并矢格林函数完备展开式一种有效途径

    This method offers an effective way to derive the complete expansions of the electrical dyadic Green 's functions in orthogonal coordinates.

    youdao

  • 本文给出单调布尔函数一类范式——单调之和展开式以及构造算法算法的实现直观的。

    The monotone sum of product expansions of monotone Boolean functions and its constructive algorithm are presented in this paper. The implementation of the algorithm is very intuitive.

    youdao

  • 在此基础提出了基于K逻辑函数oc展开式固定极性化简的新方法

    Based on it, a graphic method simplifying the OR-Coincidence (OC) expansions of a logic function under fixed polarity by using K-map is presented.

    youdao

  • 前人已有成果基础上,给出玻色子不同轨道上时对称函数非对称展开式这种展开式直接用于计算

    Based on the previous work, two expansion formulas of fully symmetric wave function for describing three bosons in different orbits are obtained, which can be used to calculate the nuclear specturm.

    youdao

  • 给出了种不含导数函数展开方法,函数连续区间内构造一个无穷级数作为函数展开式

    To construct a progression at infinity as an expansion of function in the continuous interval, a good result was achieved.

    youdao

  • 第一种推广,将方程展开式扩展负指数,可以求得方程的负指数椭圆函数解。

    The first generalization is that the expansion of solutions of equations is generalized to negative exponent, and negative exponential elliptic function solutions are obtained.

    youdao

  • 第三种方法级数基本初等函数级数展开式表示出来;

    The third one is to let series be expressed by basic elementary function's power series expansion;

    youdao

  • 得到电型并格林函数表达式由包括九个并矢分量的本展开式一个奇异组成。

    It is shown that the expression of electric-type dyadic Green's function is the sum of an eigen-mode expansion containing nine dyadic components and a singular term.

    youdao

  • 本文最后给出,角频率有偏离时,最优简化模型可以利用正弦输入函数展开式相应改变的结论。而且这种方法也适用于其它输入函数参数偏离时的情形。

    If a parameter in the inputs of the original large scale system deviates, the corresponding reduced order model can be changed by using the asymptotic expansion of the input functions.

    youdao

  • 函数进行罗伦级数展开通过边界条件得到罗伦级数展开式系数递推公式,复势函数确定应力分量位移分量。

    The complex potentials were expanded into Laurent Series whose coefficients could be expressed by recurrent relations. The stresses and displacements were then be determined by complex potentials.

    youdao

  • 采用埃尔米特插值多项式代替泰勒展开式逼近目标函数极大地降低交叉灵敏度阶数。

    Adopting the Hermite polynomial instead of the Taylor polynomial can greatly decrease the order of high-order cross sensitivity.

    youdao

  • 本文关于非线性响应理论文章的前半部分。闭路格林函数生成函的展开式闭路格林函数变换关系导出非线性响应的一般表示式

    By using the generating functional and the transformations for different forms of the closed time path Green's functions, the general equations on nonlinear response are derived.

    youdao

  • 讨论了逻辑函数与-异或或-符合代数系统中的RM展开式CRM展开式

    The RM and CRM expansions in Boolean AND-XOR and OR-COINCIDENCE algebraic system are discussed.

    youdao

  • 表达式中的两个函数利用其展开式三项作为近似式,建立一个二元线性回归方程。

    Taking the first three teams of the expression of Theis exact solution as the approximation of the two wall functions describing the drawdown, the binary linear regression expression is developed.

    youdao

  • 表达式中的两个函数利用其展开式三项作为近似式,建立一个二元线性回归方程。

    Taking the first three teams of the expression of Theis exact solution as the approximation of the two wall functions describing the drawdown, the binary linear regression expression is developed.

    youdao

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定