也是这样2,And,so,the,time,t1,divided,by,t2,通过之前的量纲分析得到2,它等于,根号下。
t1/t2 2 would be the square root of h1 divided by h2 That is the dimensional analysis argument h1/h2 that we have there.
也是这样2,And,so,the,time,t1,divided,by,t2,通过之前的量纲分析得到2,它等于,根号下。
t1/t2 2 would be the square root of h1 divided by h2 That is the dimensional analysis argument h1/h2 that we have there.
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