• 符号一样有效C无符号长吗?

    Is' long unsigned 'as valid as' unsigned long' in C?

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  • 一个符号应用程序所以需要签字

    This is an unsigned application, so you will need to sign it.

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  • 这两个除法都会避免调用除法函数另外符号的除法要符号的除法使用更少指令

    Both divisions will avoid calling the division function and the unsigned division will take fewer instructions than the signed division.

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  • 产生的完美hash()函数返回一个符号int范围为 0..(k-1),其中k最大关键字列值加 1。

    The resulting perfect hash() function returns an unsigned int value in the range 0..(k-1), where k is the maximum keyword hash value +1.

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  • 如果看到关于强制转换符号格式错误消息不必惊慌因为实际上不是错误行为。

    If you see error messages regarding forcing the format to unsigned, don't panic as this is not actually an error condition.

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  • 组件可以是一个无符号整数。

    The value of the year and month components allow an unsigned integer.

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  • 所有这些整数类型相应无符号类型。

    All these integer types also have corresponding unsigned types.

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  • 现在我们问题变得复杂点:一个二维无符号整形数组,你要找到具有最小一行。

    Now let's complicate the problem a bit: you have a two-dimensional array of unsigned integers, and you want to find the row with the smallest sum.

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  • CCSID16位无符号整数惟一地标识一个特定代码

    A CCSID is a 16-bit unsigned integer that uniquely identifies a particular code page.

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  • 字符指针字符字节声明符号类型的,这样可以防止8位字符符号扩展问题

    Declare character Pointers and character bytes as unsigned to avoid sign extension problems with 8-bit characters.

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  • 加载是18位无符号PS 3上本地存储地址的首选大小

    It loads 18-bit unsigned values, which is the perfect size for local store addresses on the PS3.

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  • 正如我们无符号整型例子中所看到的,必须保持一定的警惕性保证应用程序能够正常工作

    As we saw in the case of unsigned integers, there is a level of vigilance you must uphold to ensure your applications work as expected.

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  • 多数情况下不会发生问题但是一个IDL无符号整数取值正好落最高所限制取值范围中时,类型转换就发生不匹配的错误。

    In most situations this does not pose a problem but for the translation of an IDL unsigned integer type whose value falls inside the number range of its highest order bit there will be a mismatch.

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  • 如果符号数,符号快得

    And if it is unsigned, then it will be more faster than the signed division.

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  • 如果操作符号整数另外一个操作数是有符号整数,那么表达式的结果就是无符号整数

    If one of the operands is unsigned and the other is a signed int, the expression becomes an unsigned.

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  • 确保使用无符号整数防止符号扩展的问题。

    Ensure that an unsigned int is used where appropriate to prevent sign extension.

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  • 如果我们能够确定其中一个操作数为unsigned,那么使用符号除法更好因为要比符号除法快得多

    It will be better to use unsigned division by ensuring that one of the operands is unsigned, as this is faster than signed division.

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  • 这是一个无符号整型是执行size of操作结果

    An unsigned integer and the result of the sizeof operator.

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  • 如果一个没有后缀16进制常量32的,并且其高位被置位了,那么就可以作为符号整型进行定义

    Hexadecimal constants without a suffix are defined as an unsigned int if it will fit into 32-bits and if the high order bit is turned on.

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  • 每个分数需要转换合适的符号字节码(unsignedbyte - code)。

    Each score should be translated to its appropriate unsigned byte-code.

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  • 如果表达式混合使用符号符号32位整数赋值给个有符号的long类型,那么将其中操作数转换成64类型

    In cases where unsigned and signed 32-bit integers are mixed in an expression and assigned to a signed long, cast one of the operands to its 64-bit type.

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  • 类似地组件也支持任意无符号xsdecimal

    Similarly, the values of the seconds component allows an arbitrary unsigned xs: decimal.

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  • 天数小时分钟组件受限制,支持任意无符号xsinteger

    The values of the days, hours, and minutes components are not restricted, but allow an arbitrary unsigned xs: integer.

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  • 在将符号无符号整型作为long 类型传递就会出现问题

    The problem arises when passing the sum of signed and unsigned ints as long.

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  • 这样,单个无符号字节决定一个预测值预测 6,005,940 个测试集中打分需要 6,005,940 个字节

    Thus, a single unsigned byte would be dedicated for a predicted value, and predicting the 6,005,940 ratings of the test set would require 6,005,940 bytes.

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  • 一些处理器处理符号型数要比处理符号整型数快得多,也是一个好的习惯有利于代码的自我文档化(self- documenting)。

    Some processors can handle unsigned integer arithmetic considerably faster than signed (this is also good practice, and helps make for self-documenting code).

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  • 科学家早就发现,鸟类歌唱不是杂乱的,而是一连串规则语言符号

    Scientists already know that birds don’t sing haphazardly, but in a way that is governed by a set of linguistic rules that form strings of sounds.

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  • 科学家早就发现,鸟类歌唱不是杂乱的,而是一连串规则语言符号

    Scientists already know that birds don't sing haphazardly, but in a way that is governed by a set of linguistic rules that form strings of sounds.

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  • 是C99标准保证无符号整数二进制表示形式

    Does the C99 standard guaranteed the binary representation of unsigned int?

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  • 是C99标准保证无符号整数二进制表示形式

    Does the C99 standard guaranteed the binary representation of unsigned int?

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