但是在这段时间里，我更多使用的是离散数学而不是微积分，所以我需要复习才能够找出答案。
But, I use discrete mathematics much more than calculus these days, so I need to go back and look at how to find the answer.
我不需要真的计算通量积分。
对于剩下的愿意忍受我的人，我们继续，现在我们需要积分。
For the rest of you who are willing to bear with me, let's continue. So now let's just integrate.
也就是，如果我需要计算一个线积分，无论我取怎样的路径,只要路径是从点a到点。
OK, so the claim is if I have a line integral to compute, that it doesn't matter which path I take b as long as it goes from point a to point b.
nds的线积分，So，，line，integral，of，F。n，ds,是沿着C的线积分,需要确认一下，我写的是正确的。
F becomes the integral along C just to make sure that I give it to you correctly.
这场比赛我还是需要获得一些积分。
球队需要在联赛中度过几个愉快的星期，我们要争取很多积分，我希望这一切从下周的博尔顿开始。
We just need a couple of good weeks in the Premier League where we get a lot of points, and hopefully we can start next week against Bolton.
球队需要在联赛中度过几个愉快的星期，我们要争取很多积分，我希望这一切从下周的博尔顿开始。
We just need a couple of good weeks in the Premier League where we get a lot of points, and hopefully we can start next week against Bolton.
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