• 方程对应特征方程恒等

    The characteristic equations of the two equations are identical.

    youdao

  • 于是采用了线性形状函数表达位移分量以后,应力分量运动方程贡献必恒等于零

    Thus, if we use such form functions to represent the displacement components, the effect of internal stresses to the equations of motion vanishes identically.

    youdao

  • 通过一系列坐标变化恒等变换,将电力系统动态方程简化成三阶规范从而得到系统的分岔方程

    The dynamical equations of the system are simplified to a3-order normal form with a series of coordinate and approximately identical transformations, and a bifurcation equation is thus obtained.

    youdao

  • 通过一系列坐标变化恒等变换,将电力系统动态方程简化成三阶规范从而得到系统的分岔方程

    The dynamical equations of the system are simplified to a3-order normal form with a series of coordinate and approximately identical transformations, and a bifurcation equation is thus obtained.

    youdao

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定