如果选中,将有管理人员与您联系。
如果选中了两个元素,则可以看到上下文菜单。
如果选中了所有的方法,将会有更多的生成码。
If you leave all the methods checked, there is more generated code.
so given that we chose an odd number of people in the row, if exactly one candidate stands and that candidate is the center candidate, then that's an equilibrium.
假若我们选中行的人数为奇数,如果确实只有一个候选人参选且,那个候选人就是在中间,则那是个均衡
And if Player I chooses bottom, then center yields 2, right yields 0: 2 is bigger than 0 again.
如果参与者I选择下,选中的收益是2,选右的收益是0,2大于0
If Player I chose top, center yields 3, right yields 0: 3 is bigger than 0.
如果参与者I选择上,选中的收益是3,选右的收益为0,3大于0
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