假设我们的向量场有两个分量。
这是另一种形式,它意味着,要求出每点处向量在切向量方向的分量,我还是用之前那个向量场吧。
That is how we reformulated it. That means we take our curve and we figure out at each point how big the tangent component I guess I should probably take the same vector field as before.
我将要证明,一个只有z分量的向量场的通量,等于一个三重积分,其中被积表达式为。
I'm going to prove that the flux of a vector field that has only a z component is actually equal to the triple integral of, RzdV well, the divergence of this is just R sub z dV.
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