现已确定有四种可能的结果。
这两个选项有四种可能的组合
它的四种可能输入对应于笛卡尔图的四个点。
Its four possible inputs correspond to four points on a Cartesian graph.
Because it takes three units where there's only four choices at each position to have at least 20 unique combinations.
因为每个位点上仅有四种可能性,只有采用三个碱基一组,才能取得至少二十种不同的组合方式
It's only got one of four possible choices at each position.
每个位点上都只有四种可能性
x 4 x 4--possibilities, because I could have here, here, , , - 4 x 4 = 16.
x4x4种可能性,因为这有AGCU四种,这也是四种,4x4=16.
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