Subtract a constant from a vector's magnitude (shorten the vector) without using square root?
减去一个常数向量的大小(缩短向量),而不使用平方根?。
Obviously — and that's a bad way of saying it, I said constant the previous time — in the linear case, it's subtract by certain amount.
这么描述很不准确,我之前在,线性算法中也说了常数,它是每次减少固定的量。
Obviously-- and that's a bad way of saying it, I said constant the previous time-- in the linear case, it's subtract by certain amount.
这么描述很不准确,我之前在,线性算法中也说了常数,它是每次减少固定的量。
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