To do this asynchronously, the net traverses the distorted pattern, and at each node, n, it asks whether n's value should be set to -1 or + 1.

如果是异步完成，网络会遍历失真的图案，在每一个节点n，它会询问n的值应该设置为- 1还是+ 1。

youdao

where d(n) for a hidden node n, turns on (1) how much n influences any given output node; and (2) how much that output node itself influences the overall error of the net.

其中 d(n) 是隐藏节点 n 的函数，让我们来看（1）n 对任何给出的输出节点有多大影响；（2）输出节点本身对网络整体的误差有多少影响。

youdao

So, if we think about the second case here where we have c n minus, now we're talking about a molecule with a net charge of negative 1.

那么，如果我们考虑的是第二个例子,也就是氰离子，那么现在我们讨论的是一个净电荷量为负一的分子。

youdao

So, if we think about the second case here where we have c n minus, now we're talking about a molecule with a net charge of negative 1.

那么，如果我们考虑的是第二个例子,也就是氰离子，那么现在我们讨论的是一个净电荷量为负一的分子。

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