So, if we want to compare them, we should probably subtract them from each other. OK, so let's do the flux integral for S1 minus the flux integral for S2 of the same thing.
那么,如果我们想要比较它们,我们应该把它们相减,用S1的通量积分减掉s2的通量积分。
By implementing the plus and minus methods, I've overloaded both + and - and can now use them in my scripts. Listing 5 demonstrates their behavior to add and subtract songs from a play list.
通过实现plus和minus方法,我重载了+和-,现在可以把它们用在脚本中了。
All right, so the bonding order, you're correct, should be 2, if we subtract the number of bonding minus anti-bonding electrons and take that in 1/2.
好,你们是对的,键序为,如果我们用成键数,减去反键数除以2。
And then if we think about 3 s, 0 we want to start with 3, we subtract 1, again l is equal to 0, so minus and we have two radial nodes.
我们从3开始,减去,同样的l等于,所以减去0,我们有两个节点,这应该。
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