The signed division will take more time to execute because it rounds towards zero, while a shift rounds towards minus infinity.

有符号的除法要耗费更多的时间，因为除法是使最终结果趋向于零的，而移位则是趋向于负无穷。

youdao

We have the integral from minus infinity to plus infinity of F(x)*x*dx, and that's really--you see it's the same thing because an integral is analogous to a summation.

我们用从负无穷到正无穷的积分公式F(x)*x*dx,你看到的，这是相同的事，因为积分是类似的求和过程。

youdao

This is minus one over r, so I get m MG over r with a minus sign, and that has to be evaluated between infinity and capital R.

这是r的负值，所以在mMG/r上加-号，它处于,无穷远和R之间。

youdao

If I had taken as my interpolation scheme, my white curve here, I could go to infinity and have the equivalent of absolute zero being at infinity, minus infinity.

要注意，如果我们采用，像图中白线这样的插值方案的话,我就可以一直降温下去,相应的绝对零度点。

麻省理工公开课 - 热力学与动力学课程节选

Well, the energy at infinity is zero -K and the energy in the ground state is minus K.

无限远处的能量值为,而基态能量值为。

麻省理工公开课 - 固态化学导论课程节选

The ionization energy must then be nothing more than, that is the energy to go from the ground state here to n equals infinity, so that would be the energy at state infinity minus the energy of the ground state.

这个电离能一定不会大于，从基态到n为无限大时的能量,而是等于,无限远处的能量减去基态能量。

麻省理工公开课 - 固态化学导论课程节选